The ionization isomer of `[Cr(H_2O)_4Cl(NO_2)]Cl` is

Options

A. `[Cr(H_(2)O)_(4)(O_(2)N)]CI_(2)`
B. `[Cr(H_(2)O)_(4)CI_(2)](NO_(2)`
C. `[Cr(H_(2)O)_(4)CI(ONO)]CI`
D. `[Cr(H_(2)O)_(4)CI_(2)(NO_(2))]H_(2)O`

Answer

b

Explanation

The ionisation isomer of `[Cr(H_(2)O)_(4)CI(NO_(2))]CI` is
`[Cr(H_(2)O)_(4)CI_(2)](NO_(2))`
`CI^(Θ)` is replacedby `NO_(2)^(Θ)` in ionisation sphere
`[Cr(H_(2)O))_(4)CI(NO_(2))]Cirarr[Cr(H_(2)O)_(4)CI(NO_(2))]^(o+)CI^(Θ)`
`[Cr(H_(2)O)_(4)CI_(2)](NO_(2))rarr[Cr(H_(2)O)CI_(2)]+NO_(2)` Θ`
Both of them give different ions on dissociation .