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The octahedral complex of a metal ion M^...

The octahedral complex of a metal ion `M^(3+)` with four monodentate ligands `L_(1), L_(2),L_(3)` and `L_(4)` absorb wavelengths in the region of red greee, yellowand blue, respectively. The incresing order of ligand strength of the four ligands is:

A

`L_(3)ltL_(2)ltL_(4)ltL_(1)`

B

`L_(1)ltL_(2)ltL_(4)ltL_(3)`

C

`L_(4)ltL_(3)ltL_(2)ltL_(1)`

D

`L_(1)ltL_(3)ltL_(2)ltL_(4)`

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The correct Answer is:
d
Strong field ligands cause higher magnitude of crystal field splitting which is accompanied by the absorption of higher energy radiation
`oversetVIBGYORRARR` decreasing energy .
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Homoleptic octahedral complexes of a metal ion ' M^(3+) ' with three monodentate ligands L_(1),L_(2) and L_(3) absorb wavelengths in the region of green, blue and red respectively. The increasing order of the ligand strength is :

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According to C.F.T, attraction between the central metal ion and ligands in a complex is purely electrostatic. The transition metal which forms the central atom cation in the complex is regarded as a positive ion. It is surrounded by negative ligands or neutral molecules which have a lone apir of electrons, if the ligand is a neutral molecule such as NH_(3) , the negative and of the dipole in the molecule is directed towards the metal cation. the electrons on the central metal ion are under repulsive forces from those on the ligands. thus the electrons occupy the d-orbitals remain away from the direction of approach ligands. ltBrgt Q. The crystal field-spliting order for Cr^(3+) cation is octahedral field for ligands CH_(3)COO^(-),NH_(3),H_(2)O,CN^(-) is:

According to C.F.T, attraction between the central metal ion and ligands in a complex is purely electrostatic. The transition metal which forms the central atom cation in the complex is regarded as a positive ion. It is surrounded by negative ligands or neutral molecules which have a lone apir of electrons, if the ligand is a neutral molecule such as NH_(3) , the negative and of the dipole in the molecule is directed towards the metal cation. the electrons on the central metal ion are under repulsive forces from those on the ligands. thus the electrons occupy the d-orbitals remain away from the direction of approach ligands. Q. The crystal field-spliting order for Cr^(3+) cation is octahedral field for ligands CH_(3)COO^(-),NH_(3),H_(2)O,CN^(-) is:

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