Home
Class 12
CHEMISTRY
EDTA^(4-) i9s ethylenediamine tetraaceta...

`EDTA^(4-)` i9s ethylenediamine tetraacetate ion The total number of `N-CO-O` bond angles in `[Co(EDTA)]^(-1)` complex ion is .

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the total number of N-CO-O bond angles in the complex ion \([Co(EDTA)]^{-1}\), we will follow these steps: ### Step 1: Understand the Structure of EDTA EDTA (ethylenediaminetetraacetate) is a hexadentate ligand, meaning it can form six bonds with a metal ion. It contains two nitrogen atoms and four oxygen atoms that are part of acetate groups. ### Step 2: Draw the Structure of EDTA - Start by drawing the backbone of EDTA, which consists of two ethylene groups (CH2-CH2) connected to two nitrogen atoms. - Each nitrogen is bonded to an acetate group (C(=O)O^-). - This gives us a total of four acetate groups, each contributing one oxygen atom with a negative charge. ### Step 3: Identify Coordination Sites In the complex \([Co(EDTA)]^{-1}\): - The two nitrogen atoms and four oxygen atoms coordinate with the cobalt ion. - Thus, there are six coordination sites: two from nitrogen and four from oxygen. ### Step 4: Determine N-CO-O Bond Angles - For each nitrogen atom, we can form bond angles with the cobalt and the oxygen atoms. - Each nitrogen can form bond angles with two different oxygen atoms (one from each acetate group). ### Step 5: Count the Angles - For one nitrogen atom: - N-CO-O angle with the first oxygen. - N-CO-O angle with the second oxygen. - This gives us 2 angles per nitrogen atom. - Since there are 2 nitrogen atoms, the total number of N-CO-O angles from both nitrogen atoms is: \[ 2 \text{ (from one nitrogen)} + 2 \text{ (from the other nitrogen)} = 4 \text{ angles} \] ### Step 6: Total N-CO-O Angles - Each nitrogen contributes 2 angles, leading to a total of: \[ 4 \text{ (from both nitrogen atoms)} + 4 \text{ (from the four oxygen atoms)} = 8 \text{ N-CO-O angles} \] ### Final Answer Thus, the total number of N-CO-O bond angles in the \([Co(EDTA)]^{-1}\) complex ion is **8**. ---

To solve the problem of finding the total number of N-CO-O bond angles in the complex ion \([Co(EDTA)]^{-1}\), we will follow these steps: ### Step 1: Understand the Structure of EDTA EDTA (ethylenediaminetetraacetate) is a hexadentate ligand, meaning it can form six bonds with a metal ion. It contains two nitrogen atoms and four oxygen atoms that are part of acetate groups. ### Step 2: Draw the Structure of EDTA - Start by drawing the backbone of EDTA, which consists of two ethylene groups (CH2-CH2) connected to two nitrogen atoms. - Each nitrogen is bonded to an acetate group (C(=O)O^-). ...
Promotional Banner

Topper's Solved these Questions

  • COORDINATION COMPOUNDS

    CENGAGE CHEMISTRY ENGLISH|Exercise Archives Fill The Blanks|3 Videos
  • COORDINATION COMPOUNDS

    CENGAGE CHEMISTRY ENGLISH|Exercise Archives True/False|1 Videos
  • COORDINATION COMPOUNDS

    CENGAGE CHEMISTRY ENGLISH|Exercise Archives Assertion Reasoning|2 Videos
  • CHEMICAL KINETICS

    CENGAGE CHEMISTRY ENGLISH|Exercise Archives Subjective|23 Videos
  • D AND F BLOCK ELEMENTS

    CENGAGE CHEMISTRY ENGLISH|Exercise Archives Subjective|29 Videos

Similar Questions

Explore conceptually related problems

What is the oxidation state of the central atom in [Fe(EDTA)]^-1 complex ion.

The oxidation number of Co in the complex ion

Total number of sigma bonds present in Fe_2(CO)_9 is

Total number of Cr–O bonds in Chromate ion and dichromate ion is.

The total number of valence electrons in 4. 2g of N_3^- ion are :

Total number of moles of EDTA^(4-) required to produce octahedral complex with Mg^(2+) is

The difference between total number of lone pairs and total number of sigma -bonds in [B_(3)O_(3)(OH)_(6)]^(3-) molecular ion is:

The difference between total number of lone pairs and total number of sigma -bonds in [B_(3)O_(3)(OH)_(6)]^(3-) molecular ion is:

The O-N-O bond angle in the nitrite ion, NO_(2)^(-) , is closest to :

Assertion The total number of isomers shown by [Co(en)_(2)CI_(2)]^(o+) complex ion is three [Co(en)_(2)CI_(2)]^(2+) complex ion has an octahedral geometry .