The acidic aqueous solution of ferrous ion forms a brown complex in the presence of `NO_(3)^(Θ)` by the follwing two steps:
`[Fe(H_(2)O)_(6)]^(2+) +NO_(3)^(Θ) + H^(o+) rarr … + [Fe(H_(2)O)_(6)]^(3+) + H_(2)O`
`[Fe(H_(2)O)_(6)]^(2+) +…rarr… + H_(2)O`
Complete and balance the equations .

Explanation

To complete and balance the equations for the reaction of ferrous ion with nitrate in acidic solution, we can follow these steps:

### Step 1: Write the unbalanced equations
The first step involves the oxidation of ferrous ion \([Fe(H_2O)_6]^{2+}\) to ferric ion \([Fe(H_2O)_6]^{3+}\) by nitrate ion \((NO_3^−)\). The unbalanced equation can be written as:
\[ [Fe(H_2O)_6]^{2+} + NO_3^{-} + H^{+} \rightarrow [Fe(H_2O)_6]^{3+} + H_2O \]

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