`A,B` and `C` are three complexes of chromium(III) with the empirical formula `H_(12)O_(6)Cl_(3)Cr` All the three complexes not react with concentrated `H_(2)SO_(4)` whereas complexes `B` and `C` lose `6.75%` and `13.5%` of their original mass respectively, on treatment on treatment with conectrated `H_(2)SO_(4)` Identify `A,B` and `C` .

Explanation

To solve the problem, we need to identify the three complexes A, B, and C based on the information provided. Let's break down the solution step by step:

### Step 1: Understanding the Empirical Formula
The empirical formula given is \( \text{H}_{12}\text{O}_{6}\text{Cl}_{3}\text{Cr} \). This indicates that each complex contains chromium (Cr), three chloride ions (Cl), and a certain number of water molecules (H2O).

### Step 2: Analyzing the Reactivity with Concentrated \( \text{H}_2\text{SO}_4 \)
The problem states that complexes A, B, and C do not react with concentrated \( \text{H}_2\text{SO}_4 \), while B and C lose 6.75% and 13.5% of their original mass, respectively, when treated with it.

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