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There is ppt. of solute AB if its produ...

There is ppt. of solute AB if its product is greater than `K_(sp)` value i.e. `[A][B] gt K_(sp)`True/false

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To determine whether the statement "There is a precipitate of solute AB if its product is greater than Ksp value" is true or false, we can analyze the situation step by step. ### Step-by-Step Solution: 1. **Understanding Ksp**: - Ksp (solubility product constant) is a constant that represents the maximum product of the concentrations of the ions in a saturated solution at a given temperature. For a salt AB that dissociates into ions A⁺ and B⁻, the Ksp expression is given by: \[ K_{sp} = [A^+][B^-] \] 2. **Condition for Precipitation**: - A precipitate forms when the product of the concentrations of the ions exceeds the Ksp value. This means if: \[ [A^+][B^-] > K_{sp} \] then the solution is supersaturated, and a precipitate will form. 3. **Analyzing the Statement**: - The statement claims that there is a precipitate of solute AB if the product of the concentrations of A⁺ and B⁻ is greater than Ksp. This aligns with our understanding of Ksp and precipitation conditions. 4. **Conclusion**: - Since the condition for precipitation is indeed when the product of the concentrations of the ions exceeds Ksp, the statement is true. ### Final Answer: The statement is **True**. ---

To determine whether the statement "There is a precipitate of solute AB if its product is greater than Ksp value" is true or false, we can analyze the situation step by step. ### Step-by-Step Solution: 1. **Understanding Ksp**: - Ksp (solubility product constant) is a constant that represents the maximum product of the concentrations of the ions in a saturated solution at a given temperature. For a salt AB that dissociates into ions A⁺ and B⁻, the Ksp expression is given by: \[ K_{sp} = [A^+][B^-] ...
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A solution which remains in equilibrium with undissolved solute is said to be saturated. The concentration of a saturated solution at a given temperature is called solubility. The product of concentration of ions in a saturated solution of an electrolyte at a given temperature, is called solubility product (K_(sp)) . For the electrolyte, A_(x),B_(y),:A_(x),B_(y(s)) rarr xA^(y+)+ y^(Bx-) , with solubility S, the solubility product (K_(sp)) =x^(x)xxy^(y) xx s^(x+y) . While calculating the solubility of a sparingly soluble salt in the presence of some strong electrolyte containing a common ion, the common ion concentration is practically equal to that of strong electrolyte. If in a solution, the ionic product of an clectrolyte exceeds its K_(sp) , value at a particular temperature, then precipitation occurs. The solubility of PbSO_(4) , in water is 0.303 g/l at 25^(@) C, its solubility product at that temperature is

A solution which remains in equilibrium with undissolved solute is said to be saturated. The concentration of a saturated solution at a given temperature is called solubility. The product of concentration of ions in a saturated solution of an electrolyte at a given temperature, is called solubility product (K_(sp)) . For the electrolyte, A_(x),B_(y),:A_(x),B_(y(s)) rarr xA^(y+)+ y^(Bx-) , with solubility S, the solubility product (K_(sp)) =x^(x)xxy^(y) xx s^(x+y) . While calculating the solubility of a sparingly soluble salt in the presence of some strong electrolyte containing a common ion, the common ion concentration is practically equal to that of strong electrolyte. If in a solution, the ionic product of an clectrolyte exceeds its K_(sp) , value at a particular temperature, then precipitation occurs. The solubility of PbSO_(4) , in water is 0.303 g/l at 25^(@) C, its solubility at that temperature is

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CENGAGE CHEMISTRY ENGLISH-QUALITATIVE INORGANIC SALT ANALYSIS-Exercises (True And False )
  1. Turnbull's blue and prussian's blue respectively are KFe^(II)[Fe^(...

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  2. K(sp) of Mg(OH)(2) is 1xx10^(-12), 0.01M MgCI(2) will be precipitating...

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  3. There is ppt. of solute AB if its product is greater than K(sp) val...

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  4. Chlorine gas is passed into a solution containing KF, KI and KBr and C...

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  5. When H(2)S gas is passed into aq ZnCl(2) solution white ppt of ZnS is...

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  6. Dilute H(2)SO(4) can be used in group of dil HCI. True/False

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  7. NH(4)CI can be replaced by (NH(4))(2)SO(4) in group III.

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  8. Alkaline solution of NH(4)Cl gives ppt with K(2)HgI(4)

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  9. When KNO(2) and CH(2)COOH is added as CoCl(2) solution, yellow ppt of ...

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  10. K(4)[Fe(CN)(6)] is used to test Cu^(2+),Fe^(2+),Zn^(2+),Cd^(2+)

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  11. Hg(2)Cl(2) is black ened by NH(3) due to formation of iodide of mi...

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  12. White ppt of PbCl(2) is soluble in aq NH(3). (T/F)

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  13. If acidified solution of K(2)Cr(2)O(7) turm green on addition of...

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  14. In group II, Formqation of whichsh tarbidity on dilation with H(2)O ...

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  15. NaOH can be used to seprate Al(OH)(3) and Zn(OH)(2) . (T/F)

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  16. NH(4)SCN can be used to make distanction between Cu^(2+) and Co^(2+)...

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  17. Yellow ammonium sulphide (YAS) can be used to seprate SnS and As(2)S...

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  18. NaOH can be used to seprate Al(OH)(3) and Zn(OH)(2) . (T/F)

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  19. AlCl(2) is soluble is axcess of NaOH forming sodium metaaluminate ...

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  20. BaBr(2) gives yellow ppt with AgNO(3) as well as with K(2)CrO(4). (T...

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