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When H(2)S gas is passed into aq ZnCl(2)...

When `H_(2)S` gas is passed into aq `ZnCl_(2)` solution white ppt of ZnS is obtained. Explain.

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### Step-by-Step Solution: 1. **Understanding the Reactants**: - We start with an aqueous solution of zinc chloride (ZnCl₂) and hydrogen sulfide gas (H₂S). Zinc chloride dissociates in water to give zinc ions (Zn²⁺) and chloride ions (Cl⁻). 2. **Reaction of H₂S with Zn²⁺**: - When H₂S gas is bubbled into the ZnCl₂ solution, the hydrogen sulfide reacts with the zinc ions (Zn²⁺) present in the solution. The sulfide ions (S²⁻) from H₂S combine with Zn²⁺ to form zinc sulfide (ZnS), which is insoluble in water. 3. **Formation of Precipitate**: - The reaction can be represented as: \[ \text{ZnCl}_2 (aq) + \text{H}_2\text{S} (g) \rightarrow \text{ZnS} (s) + 2 \text{HCl} (aq) \] - In this reaction, zinc sulfide (ZnS) precipitates out of the solution as a white solid, while hydrochloric acid (HCl) remains in the solution. 4. **Properties of Zinc Sulfide**: - Zinc sulfide (ZnS) is known to be insoluble in water and in dilute acids. It appears as a white precipitate when formed. 5. **Further Reactions**: - If zinc sulfide is treated with caustic soda (sodium hydroxide, NaOH), it can form a white precipitate of zinc hydroxide (Zn(OH)₂). The reaction can be represented as: \[ \text{ZnS} + 2 \text{NaOH} \rightarrow \text{Zn(OH)}_2 (s) + \text{Na}_2\text{S} \] - On heating with excess NaOH, sodium zincate (Na₂ZnO₂) is formed: \[ \text{Zn(OH)}_2 + 2 \text{NaOH} \rightarrow \text{Na}_2\text{ZnO}_2 + 2 \text{H}_2\text{O} \] 6. **Dissolution of Zinc Sulfide**: - If zinc sulfide is treated with dilute hydrochloric acid, it dissolves to regenerate zinc chloride and hydrogen sulfide: \[ \text{ZnS} + 2 \text{HCl} \rightarrow \text{ZnCl}_2 + \text{H}_2\text{S} \] ### Summary: When H₂S gas is passed into an aqueous solution of ZnCl₂, zinc ions react with sulfide ions to form a white precipitate of zinc sulfide (ZnS). This reaction highlights the insolubility of ZnS in water and its behavior in the presence of caustic soda and acids.

### Step-by-Step Solution: 1. **Understanding the Reactants**: - We start with an aqueous solution of zinc chloride (ZnCl₂) and hydrogen sulfide gas (H₂S). Zinc chloride dissociates in water to give zinc ions (Zn²⁺) and chloride ions (Cl⁻). 2. **Reaction of H₂S with Zn²⁺**: - When H₂S gas is bubbled into the ZnCl₂ solution, the hydrogen sulfide reacts with the zinc ions (Zn²⁺) present in the solution. The sulfide ions (S²⁻) from H₂S combine with Zn²⁺ to form zinc sulfide (ZnS), which is insoluble in water. ...
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  6. Dilute H(2)SO(4) can be used in group of dil HCI. True/False

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  7. NH(4)CI can be replaced by (NH(4))(2)SO(4) in group III.

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  8. Alkaline solution of NH(4)Cl gives ppt with K(2)HgI(4)

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  9. When KNO(2) and CH(2)COOH is added as CoCl(2) solution, yellow ppt of ...

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  10. K(4)[Fe(CN)(6)] is used to test Cu^(2+),Fe^(2+),Zn^(2+),Cd^(2+)

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  11. Hg(2)Cl(2) is black ened by NH(3) due to formation of iodide of mi...

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  12. White ppt of PbCl(2) is soluble in aq NH(3). (T/F)

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  13. If acidified solution of K(2)Cr(2)O(7) turm green on addition of...

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  14. In group II, Formqation of whichsh tarbidity on dilation with H(2)O ...

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  15. NaOH can be used to seprate Al(OH)(3) and Zn(OH)(2) . (T/F)

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  16. NH(4)SCN can be used to make distanction between Cu^(2+) and Co^(2+)...

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  18. NaOH can be used to seprate Al(OH)(3) and Zn(OH)(2) . (T/F)

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  20. BaBr(2) gives yellow ppt with AgNO(3) as well as with K(2)CrO(4). (T...

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