Alkaline solution of `NH_(4)Cl` gives ppt with `K_(2)HgI_(4)`

Explanation

To determine whether the statement "Alkaline solution of NH4Cl gives precipitate with K2HgI4" is true or false, we will analyze the reaction step by step.

### Step 1: Identify the Reactants
The reactants in this case are:
- Ammonium chloride (NH4Cl)
- Nessler's reagent (K2HgI4)

### Step 2: Understand the Conditions
The statement specifies that the reaction occurs in an alkaline solution. An alkaline solution typically involves the presence of a base, such as potassium hydroxide (KOH).

### Step 3: Reaction of Ammonium Chloride with Nessler's Reagent
When ammonium chloride is mixed with Nessler's reagent in an alkaline medium, the following reaction takes place:

1. **Dissociation of NH4Cl**: In an alkaline solution, NH4Cl dissociates to give NH4⁺ ions.
2. **Reaction with Nessler's Reagent**: The ammonium ions (NH4⁺) react with the components of Nessler's reagent (K2HgI4) in the presence of the base (KOH).

### Step 4: Write the Balanced Chemical Equation
The balanced chemical equation for the reaction can be represented as follows:

\[ 2 \text{K}_2\text{HgI}_4 + 4 \text{KOH} + 2 \text{NH}_4\text{Cl} \rightarrow 2 \text{Hg}_2\text{NH}_2\text{Cl} + 7 \text{KI} + 3 \text{H}_2\text{O} \]

### Step 5: Formation of Precipitate
The product of this reaction includes a brown precipitate of mercury (II) amidochloride (Hg2NH2Cl), which is formed as a result of the reaction. This brown precipitate indicates that a reaction has occurred.

### Conclusion
Since the alkaline solution of NH4Cl does indeed produce a precipitate when reacted with K2HgI4, we conclude that the statement is **true**.

### Final Answer
**True**: Alkaline solution of NH4Cl gives a precipitate with K2HgI4.

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