Nitrite and nitrite both respond to ring test Nitrate are removed by heating with

Options

A. conc `HNO_(3)`
B. `NH_(4)CI`
C. Conc `H_(2)SO_(4)`
D. `MnO_(2)`

Answer

To solve the question regarding the removal of nitrate ions by heating with ammonium chloride, we can break it down into a series of steps:

### Step-by-Step Solution:

1. **Understanding the Compounds**:
- We have two compounds: nitrite (NO2^-) and nitrate (NO3^-).
- The question mentions that both respond to the ring test, which is a qualitative test to identify the presence of nitrites and nitrates.

2. **Identifying the Reactant**:
- The question states that nitrates are removed by heating with ammonium chloride (NH4Cl).

3. **Reaction with Ammonium Chloride**:
- When sodium nitrite (NaNO2) is treated with ammonium chloride (NH4Cl), the following reaction occurs:
\[ \text{NaNO}_2 + \text{NH}_4\text{Cl} \rightarrow \text{NaCl} + \text{NH}_4\text{NO}_2 \]
- Here, sodium chloride (NaCl) and ammonium nitrite (NH4NO2) are formed.

4. **Heating Ammonium Nitrite**:
- The next step involves heating the ammonium nitrite (NH4NO2). Upon heating, ammonium nitrite decomposes to produce nitrogen gas (N2) and water (H2O):
\[ \text{NH}_4\text{NO}_2 \xrightarrow{\text{heat}} \text{N}_2 + 2\text{H}_2\text{O} \]

5. **Conclusion**:
- Therefore, the correct answer to the question is that nitrates are removed by heating with ammonium chloride.

### Final Answer:
**Nitrates are removed by heating with ammonium chloride (NH4Cl).**