Chromyl chloride test is preformed for the detection of `CI^(Theta)` A salt solution containing `CI^(Theta)` ion is heated with `K_(2)Cr_(2)O_(7)` and cone `H_(2)SO_(4)` orange red vapour of `Cr_O(2)CI_(2)`are obatined .On passing these supour through a soln of `NaOH` a yellow ppt ,due to `Na_(2)CrO_(2)` is obtained if these vapour are dissolve in `H_(2)O` and acetin acid and lead acetate solution is added then

Options

A. The solution will remain colour less
B. The solution will become dark green
C. The solution will become brown
D. A yellow ppt will be obtained

Answer

To solve the question regarding the Chromyl chloride test for the detection of chloride ions, we will follow a systematic approach:

### Step-by-Step Solution:

1. **Understanding the Chromyl Chloride Test**:
- The Chromyl chloride test is specifically used to detect the presence of chloride ions (Cl⁻) in a salt solution.

2. **Reactants**:
- A salt solution containing chloride ions (e.g., potassium chloride, KCl) is mixed with potassium dichromate (K₂Cr₂O₇) and concentrated sulfuric acid (H₂SO₄).

3. **Heating the Mixture**:
- Upon heating this mixture, chromyl chloride (CrO₂Cl₂) is formed, which is characterized by its orange-red vapors.

4. **Passing Vapors through NaOH**:
- The orange-red vapors of CrO₂Cl₂ are then passed through a solution of sodium hydroxide (NaOH). This results in the formation of sodium chromate (Na₂CrO₄), which appears as a yellow precipitate.

5. **Dissolving in Water and Acetic Acid**:
- If the vapors are dissolved in water and acetic acid (CH₃COOH), and then lead acetate (Pb(CH₃COO)₂) is added, a further reaction occurs.

6. **Formation of Lead Chromate**:
- The reaction between sodium chromate and lead acetate leads to the formation of lead chromate (PbCrO₄), which is a yellow precipitate. This confirms the presence of chloride ions.

7. **Conclusion**:
- The final observation is a yellow precipitate of lead chromate (PbCrO₄), which indicates the successful detection of chloride ions in the original salt solution.

### Final Answer:
The yellow precipitate obtained at the end of the reaction confirms the presence of chloride ions.

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