With `Cu^(2+)` ions `[F(CN)_(6)]^(4-)` gives a ……..ppt of `Cu_(2)[Fe(CN)_(6)]` (Cupric ferro cyanide)

Options

A. Blue
B. Green
C. chocolate
D. White

Answer

To solve the question regarding the reaction between `Cu^(2+)` ions and `[F(CN)_(6)]^(4-)`, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants:**
- The reactants in this reaction are `Cu^(2+)` ions (copper(II) ions) and `[Fe(CN)_(6)]^(4-)` (ferrocyanide ion).

2. **Understand the Reaction:**
- When `Cu^(2+)` ions react with `[Fe(CN)_(6)]^(4-)`, they form a complex compound known as cupric ferrocyanide.

3. **Write the Reaction Equation:**
- The chemical reaction can be represented as:
\[ 2Cu^{2+} + [Fe(CN)_{6}]^{4-} \rightarrow Cu_{2}[Fe(CN)_{6}] \]

4. **Identify the Product:**
- The product formed from this reaction is `Cu_{2}[Fe(CN)_{6}]`, which is known as cupric ferrocyanide.

5. **Determine the Characteristics of the Precipitate:**
- The precipitate formed in this reaction is known to have a specific color. In this case, cupric ferrocyanide is characterized by a chocolate brown color.

6. **Conclude the Answer:**
- Therefore, the answer to the question is that the reaction gives a **chocolate brown precipitate** of `Cu_{2}[Fe(CN)_{6}]`.

### Final Answer:
The precipitate formed is a **chocolate brown precipitate** of `Cu_{2}[Fe(CN)_{6}]` (cupric ferrocyanide).

---