With `Fe^(3+) `ions `[Fe(CN)_(6)]^(4-)` gives prussian blue colouration due to the formation of ferri- ferro cyanide `Fe[Fe(CN)_(6)]_(2)` while with `NH_(4)SCN,Fe^(3+)` ion gives……. Colouration

Options

A. Deep red
B. Blue
C. Brown
D. Green

Answer

To solve the question regarding the color change when `Fe^(3+)` ions react with `NH4SCN`, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**: The reactants in this case are `Fe^(3+)` ions and `NH4SCN` (ammonium thiocyanate).

2. **Write the Reaction**: When `Fe^(3+)` ions react with `NH4SCN`, they form ferric thiocyanate. The balanced chemical equation for this reaction is:
\[ Fe^{3+} + 3 NH_4SCN \rightarrow Fe(SCN)_3 + 3 NH_4^+ \]

3. **Identify the Product**: The product formed is `Fe(SCN)3`, which is known as ferric thiocyanate.

4. **Determine the Color of the Product**: Ferric thiocyanate (`Fe(SCN)3`) is known to produce a deep red coloration when formed in solution.

5. **Conclusion**: Therefore, when `Fe^(3+)` ions react with `NH4SCN`, the resulting color is deep red.

### Final Answer:
The coloration produced when `Fe^(3+)` ions react with `NH4SCN` is **deep red**.

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