Home
Class 12
CHEMISTRY
DMG gives a rosy red crystalline ppt wit...

DMG gives a rosy red crystalline ppt with

A

`Zn^(2+)`

B

`Ni^(2+)`

C

`Cu^(2+)`

D

`Mn^(2+)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question "DMG gives a rosy red crystalline ppt with", we will analyze the options provided and determine which metal ion reacts with dimethylglyoxime (DMG) to form a rosy red precipitate. ### Step-by-Step Solution: 1. **Understanding DMG**: - DMG stands for dimethylglyoxime, which is a reagent used to detect certain metal ions, particularly nickel (Ni²⁺). 2. **Identifying the Metal Ions**: - The options given are: - Serum 2+ (which seems to be a typo and likely refers to some metal ion), - Ni²⁺ (Nickel), - Cu²⁺ (Copper), - Mn²⁺ (Manganese). 3. **Reactions of DMG**: - DMG forms a characteristic rosy red precipitate when it reacts with nickel ions in solution. This is a well-known qualitative test for nickel. 4. **Analyzing Each Option**: - **Serum 2+**: Not a standard notation for any known metal ion. - **Ni²⁺**: Known to form a rosy red precipitate with DMG. - **Cu²⁺**: Forms a different color precipitate (usually a light pink or beige) with DMG. - **Mn²⁺**: Does not form a precipitate with DMG. 5. **Conclusion**: - Based on the above analysis, the correct answer is **Ni²⁺**, as it is the only ion that forms a rosy red crystalline precipitate with DMG. ### Final Answer: DMG gives a rosy red crystalline precipitate with **Ni²⁺**. ---
Promotional Banner

Topper's Solved these Questions

  • QUALITATIVE INORGANIC SALT ANALYSIS

    CENGAGE CHEMISTRY ENGLISH|Exercise Viva Voce Questions And Part-A (Analysis Of Anions)|30 Videos
  • QUALITATIVE INORGANIC SALT ANALYSIS

    CENGAGE CHEMISTRY ENGLISH|Exercise Viva Voce Questions And Part-B (Dry Tests)|9 Videos
  • QUALITATIVE INORGANIC SALT ANALYSIS

    CENGAGE CHEMISTRY ENGLISH|Exercise Ex 8.1|14 Videos
  • P-BLOCK GROUP 18 ELEMENTS - THE INERT GASES

    CENGAGE CHEMISTRY ENGLISH|Exercise Ex 5.1 (Objective)|14 Videos
  • REDUCTION AND OXIDATION REACTION OF ORGANIC COMPOUNDS

    CENGAGE CHEMISTRY ENGLISH|Exercise SUBJECTIVE TYPE|4 Videos

Similar Questions

Explore conceptually related problems

Which of the following compounds will give a coloured crystalline compound with ?

A crystalline solid

which of the following compound will give a bright orange yellow crystalline compound with :

A solution of a metal ion when treated with KI solution gives a red precipitate which dissolves in excess of KI solution to give a colourless solution. Moreover, the solution of the same metal ion on treatment with the solution of cobalt (II) thiocyanate gives rise to a deep blue crystalline precipitate. The metal ion is

A solution of a metal ion when treated with KI gives a red precipitate which dissolves in excess KI to give a colourless solution. Moreover, the solution of metal ion on treatment with a solution of cobalt (II) thiocyanate gives rise to a deep blue crystalline precipitate. The metal ion is

A solution of a metal ion when treated with KI gives a red precipitate which dissolves in excess KI to give a colourless solution.Moreover, the solution of metal ion on treatment with a solution of cobalt (II) thiocyanate gives rise to a deep blue crystalline precipitate.The metal ion is:

A solutionf of a metal ion when treated with KI gives a red precipitate which dissolves in excess KI to give a colourless solution.Moreover, the solution of metal ion on treatment with a solution of cobalt (II) thiocyanate gives rise to a deep-blue crystalline precipitate. The metal ions is

AgNO_3 gives red ppt. with.

The salt which in solution gives a pale green ppt. with NaOH soln. & a white ppt. with barium chloride soln is:

NiCI_(2) in the presence of dimethy1 glyoxime (DMG) gives a complex which precipitates in the presence of NH_(4)OH giving a bright red colour . (a) Draw its structure and show H bonding (b) Give the oxidation state of Ni and its hybridisation (c ) Predict whether it is paramagnetic or dimagnetic .

CENGAGE CHEMISTRY ENGLISH-QUALITATIVE INORGANIC SALT ANALYSIS-Ex 8.2
  1. Which pair would not be expected to form precipitate when solution ...

    Text Solution

    |

  2. Which one of the following can be used in place of NH(4)Cl for ident...

    Text Solution

    |

  3. Conc HNO(3) is added before proceeding to test for group III. This...

    Text Solution

    |

  4. In IV th group the ppt of Mn(OH)(2) in excess of NaOH , turns brown ...

    Text Solution

    |

  5. Mg is not precipitate in group V because

    Text Solution

    |

  6. In group V ,(NH(4))(2)CO(3) is added to precipitate out the carbonate...

    Text Solution

    |

  7. DMG gives a rosy red crystalline ppt with

    Text Solution

    |

  8. In the presence of dilute HCl, H(2)S results in the precipitation of g...

    Text Solution

    |

  9. Prussian's blue is formed when Fe^(+2) ions are added to K(4)[Fe(CN...

    Text Solution

    |

  10. Turnbull's blue is formed when Fe^(+2) ions are added to K(3)[Fe(CN)(...

    Text Solution

    |

  11. If group IV the ppt of Zn(OH)(2) dissolve in excess of NaOH due to t...

    Text Solution

    |

  12. Br(2) water in NaOH soin .Oxidises Mn(OH)(2) to a…. Ppt due to the fo...

    Text Solution

    |

  13. Brown ppt ,of Mn(OH)2 on boiling with PbO(2) and cone HNO(3) yields...

    Text Solution

    |

  14. A precipitate of ……would be obtained on adding HCI to a solution of ...

    Text Solution

    |

  15. A precipitate of ……would be obtained on adding HCI to a solution of ...

    Text Solution

    |

  16. Which of the sulphides of group II is orange ?

    Text Solution

    |

  17. Which of the sulphides of group II is black or brownish black?

    Text Solution

    |

  18. On passing H(2)S gas into first group filtrate sometimes yellow turbid...

    Text Solution

    |

  19. The sodium carbonate beat test in which Na(2)CO(3) is used insteal o...

    Text Solution

    |

  20. Orange coloured sodium cobaltinitrite Na(3)[Co(NO(3))(6)] is used fo...

    Text Solution

    |