Prussian's blue is formed when `Fe^(+2)` ions are added to `K_(4)[Fe(CN)_(6)]` Prussian's blue is

Options

A. `Fe_(4)[Fe(CN)_(6)]_(3)`
B. `Fe_(3)[Fe(CN)_(6)]_(2)`
C. `Fe_(2)[Fe(CN)_(6)]`
D. All

Answer

To solve the question regarding the formation of Prussian's blue when Fe²⁺ ions are added to K₄[Fe(CN)₆], we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants are K₄[Fe(CN)₆] (potassium ferrocyanide) and Fe²⁺ ions.

2. **Understand the Reaction**:
- When Fe²⁺ ions are added to K₄[Fe(CN)₆], they react to form a complex compound. The reaction can be represented as:
\[ K_4[Fe(CN)_6] + 4 Fe^{2+} \rightarrow Fe_4[Fe(CN)_6]_3 + 12 KCl \]
- In this reaction, four Fe²⁺ ions combine with one molecule of potassium ferrocyanide.

3. **Identify the Product**:
- The product formed is Fe₄[Fe(CN)₆]₃, which is known as Prussian blue.

4. **Determine the Correct Option**:
- Among the options given (Fe₄[Fe(CN)₆]₃, Fe₃[Fe(CN)₆]₂, Fe₂[Fe(CN)₆]), the correct formula for Prussian blue is Fe₄[Fe(CN)₆]₃.

5. **Final Answer**:
- Therefore, the correct answer is option A: Fe₄[Fe(CN)₆]₃.