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If group IV the ppt of Zn(OH)(2) dissolv...

If group IV the ppt of `Zn(OH)_(2)` dissolve in excess of `NaOH` due to the formation of

A

`Na_(2)ZnO_(2)`

B

`NaZnO_(2)`

C

`Zn`

D

`Na_(3)ZnO_(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the dissolution of zinc hydroxide in excess sodium hydroxide, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Compound**: The compound in question is zinc hydroxide, which has the chemical formula `Zn(OH)₂`. It is known to be a white precipitate. 2. **Understand the Reaction with NaOH**: When excess sodium hydroxide (NaOH) is added to zinc hydroxide, a reaction occurs. The hydroxide ions from NaOH can react with the zinc ions from zinc hydroxide. 3. **Write the Reaction**: The reaction can be represented as follows: \[ Zn(OH)_2 (s) + 2 NaOH (aq) \rightarrow Na_2ZnO_2 (aq) + 2 H_2O (l) \] Here, zinc hydroxide reacts with sodium hydroxide to form sodium zincate and water. 4. **Identify the Product**: The product formed in this reaction is sodium zincate, which can be represented as `Na₂ZnO₂`. This compound is soluble in water. 5. **Conclusion**: Therefore, the answer to the question is that the precipitate of zinc hydroxide dissolves in excess sodium hydroxide due to the formation of sodium zincate. ### Final Answer: The precipitate of `Zn(OH)₂` dissolves in excess `NaOH` due to the formation of sodium zincate, `Na₂ZnO₂`. ---
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