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A precipitate of ……would be obtained on...

A precipitate of ……would be obtained on adding HCI to a solution of `As_(2)S_(3)` in yellow ammonium salphide

A

`As_(2)S_(3)`

B

`AsS_(3)`

C

`As_(2)S_(6)`

D

`AsS_(2)`

Text Solution

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The correct Answer is:
To solve the problem step by step, we will analyze the reaction that occurs when hydrochloric acid (HCl) is added to a solution of arsenic trisulfide (As₂S₃) in yellow ammonium sulfide. ### Step 1: Identify the Components We start with a solution of arsenic trisulfide (As₂S₃) in yellow ammonium sulfide (NH₄)₂S. Yellow ammonium sulfide is a source of sulfide ions (S²⁻) which can react with arsenic species. **Hint:** Recognize the compounds involved and their states in the solution. ### Step 2: Reaction with Ammonium Sulfide When As₂S₃ is mixed with yellow ammonium sulfide, a reaction occurs that leads to the formation of a thiosalt. The reaction can be represented as follows: \[ \text{As}_2\text{S}_3 + 3 \text{(NH}_4)_2\text{S} \rightarrow 2 \text{NH}_4\text{AsS}_4 \] This thiosalt is ammonium arsenic tetrasulfide (NH₄)₃AsS₄. **Hint:** Look for the formation of new compounds when reactants are mixed. ### Step 3: Reaction with Hydrochloric Acid Next, when hydrochloric acid (HCl) is added to the thiosalt (NH₄)₃AsS₄, a precipitate forms. The reaction can be summarized as: \[ \text{NH}_4\text{AsS}_4 + 6 \text{HCl} \rightarrow \text{As}_2\text{S}_6 + 6 \text{NH}_4\text{Cl} + 3 \text{H}_2\text{S} \] In this reaction, arsenic hexasulfide (As₂S₆) precipitates out of the solution. **Hint:** Consider how acids can react with sulfides to form precipitates. ### Step 4: Identify the Precipitate From the above reaction, we can see that the precipitate formed when HCl is added to the solution is arsenic hexasulfide (As₂S₆). **Hint:** Focus on the final product of the reaction to determine the precipitate. ### Conclusion Thus, the precipitate obtained on adding HCl to a solution of As₂S₃ in yellow ammonium sulfide is As₂S₆. **Final Answer:** The precipitate formed is **As₂S₆**.
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CENGAGE CHEMISTRY ENGLISH-QUALITATIVE INORGANIC SALT ANALYSIS-Ex 8.2
  1. Which pair would not be expected to form precipitate when solution ...

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  2. Which one of the following can be used in place of NH(4)Cl for ident...

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  3. Conc HNO(3) is added before proceeding to test for group III. This...

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  4. In IV th group the ppt of Mn(OH)(2) in excess of NaOH , turns brown ...

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  5. Mg is not precipitate in group V because

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  6. In group V ,(NH(4))(2)CO(3) is added to precipitate out the carbonate...

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  7. DMG gives a rosy red crystalline ppt with

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  8. In the presence of dilute HCl, H(2)S results in the precipitation of g...

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  9. Prussian's blue is formed when Fe^(+2) ions are added to K(4)[Fe(CN...

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  10. Turnbull's blue is formed when Fe^(+2) ions are added to K(3)[Fe(CN)(...

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  11. If group IV the ppt of Zn(OH)(2) dissolve in excess of NaOH due to t...

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  12. Br(2) water in NaOH soin .Oxidises Mn(OH)(2) to a…. Ppt due to the fo...

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  13. Brown ppt ,of Mn(OH)2 on boiling with PbO(2) and cone HNO(3) yields...

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  14. A precipitate of ……would be obtained on adding HCI to a solution of ...

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  15. A precipitate of ……would be obtained on adding HCI to a solution of ...

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  16. Which of the sulphides of group II is orange ?

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  17. Which of the sulphides of group II is black or brownish black?

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  18. On passing H(2)S gas into first group filtrate sometimes yellow turbid...

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  19. The sodium carbonate beat test in which Na(2)CO(3) is used insteal o...

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  20. Orange coloured sodium cobaltinitrite Na(3)[Co(NO(3))(6)] is used fo...

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