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The sodium carbonate beat test in whic...

The sodium carbonate beat test in which `Na_(2)CO_(3)` is used insteal of borax .it is suitable to chromium and

A

Mn

B

Cu

C

Fe

D

Ni

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### Step-by-Step Solution: 1. **Understanding the Sodium Carbonate Bead Test**: The sodium carbonate bead test is a qualitative analysis method used to detect certain metal ions by heating sodium carbonate (Na₂CO₃) on a platinum wire and observing the color of the bead formed when the metal salt is added. 2. **Identifying the Metals**: The question specifies that the sodium carbonate bead test is suitable for chromium. We need to determine which other metal from the given options (manganese, copper, iron, nickel) is also suitable for this test. 3. **Reactions Involved**: - For **Chromium (Cr)**: When chromium oxide (Cr₂O₃) is heated with sodium carbonate, it forms sodium chromate (Na₂CrO₄) and releases carbon dioxide (CO₂). The resulting sodium chromate gives a characteristic yellow bead. - For **Manganese (Mn)**: When manganese oxide (MnO) is heated with sodium carbonate, it forms sodium manganate (Na₂MnO₄) and also releases carbon dioxide. The resulting sodium manganate gives a characteristic green bead. 4. **Analyzing the Options**: - **Manganese**: As discussed, it forms a green bead. - **Copper**: Typically does not produce a characteristic bead in this test. - **Iron**: Generally does not yield a specific bead color in this test. - **Nickel**: Also does not produce a characteristic bead. 5. **Conclusion**: The sodium carbonate bead test is suitable for both chromium and manganese. Therefore, the correct answer to the question is **manganese**. ### Final Answer: The sodium carbonate bead test is suitable for **manganese**. ---
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CENGAGE CHEMISTRY ENGLISH-QUALITATIVE INORGANIC SALT ANALYSIS-Ex 8.2
  1. Which pair would not be expected to form precipitate when solution ...

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  2. Which one of the following can be used in place of NH(4)Cl for ident...

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  3. Conc HNO(3) is added before proceeding to test for group III. This...

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  4. In IV th group the ppt of Mn(OH)(2) in excess of NaOH , turns brown ...

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  5. Mg is not precipitate in group V because

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  6. In group V ,(NH(4))(2)CO(3) is added to precipitate out the carbonate...

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  7. DMG gives a rosy red crystalline ppt with

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  8. In the presence of dilute HCl, H(2)S results in the precipitation of g...

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  9. Prussian's blue is formed when Fe^(+2) ions are added to K(4)[Fe(CN...

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  10. Turnbull's blue is formed when Fe^(+2) ions are added to K(3)[Fe(CN)(...

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  11. If group IV the ppt of Zn(OH)(2) dissolve in excess of NaOH due to t...

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  12. Br(2) water in NaOH soin .Oxidises Mn(OH)(2) to a…. Ppt due to the fo...

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  13. Brown ppt ,of Mn(OH)2 on boiling with PbO(2) and cone HNO(3) yields...

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  14. A precipitate of ……would be obtained on adding HCI to a solution of ...

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  15. A precipitate of ……would be obtained on adding HCI to a solution of ...

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  16. Which of the sulphides of group II is orange ?

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  17. Which of the sulphides of group II is black or brownish black?

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  18. On passing H(2)S gas into first group filtrate sometimes yellow turbid...

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  19. The sodium carbonate beat test in which Na(2)CO(3) is used insteal o...

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  20. Orange coloured sodium cobaltinitrite Na(3)[Co(NO(3))(6)] is used fo...

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