Give the formula and describe the structure of a noble gas which is isostructural with
(i). `Icl_4^(ɵ)`
(ii). `I Br_2^(ɵ)`
(iii). `BrO_3`

Explanation

To solve the problem, we need to identify the noble gas compounds that are isostructural with the given species: ICl4^-, IBr2^-, and BrO3^-. Let's go through each one step by step.

### Step 1: Identify the structure of ICl4^-
- **Formula**: ICl4^-
- **Valence Electrons**: Iodine (I) has 7 valence electrons, and each chlorine (Cl) has 7 valence electrons. The negative charge adds one more electron. Thus, the total number of valence electrons is:
\[ 7 + (4 \times 7) + 1 = 30 \text{ electrons} \]
...