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Assertion : Hydrochloric acid is not use...

Assertion : Hydrochloric acid is not used to acidify a `KMnO_(4)` solution in volumetric analysis of `Fe^(2+)` and `C_(2) O_(4)^(2-)` because.
Reason : Part of the oxygen produced from `KMnO_(4)` and `HCl` is used up in oxidising `HCl` to `Cl_(2)`.

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To solve the question, we will analyze the assertion and the reason provided, and then conclude whether they are correct and if the reason supports the assertion. ### Step 1: Understand the Assertion The assertion states that hydrochloric acid (HCl) is not used to acidify a potassium permanganate (KMnO4) solution in volumetric analysis of Fe²⁺ and C₂O₄²⁻. ### Step 2: Understand the Reason The reason given is that part of the oxygen produced from KMnO₄ and HCl is used up in oxidizing HCl to Cl₂. ...
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Why is HCl not used to acidify a permanganate solution in volumetric estimation of Fe^(2 + ) or C_2O_4^(2-) ?

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Volumetric titrations involving KMnO_(4) , are carried out only in presence of dilute H_(2)SO_(4) but not in the presence of HCI or HNO_(3) This is because oxygen produced from KMnO_(4) + dil: H_(2)SO_(4) , is used only for oxidizing the reducing agent. Moreover, H2SO4 does not give any oxygen of its own to oxidize the reducing agent. In case HCI is used, the oxygen produced from KMnO_(4) + HCI is partly used up to oxidize HCI and in case HNO_(3) is used, it itself acts as oxidizing agent and partly oxidizes the reducing agent. KMnO_(4) , in various mediums gives following products Mn^(7+)overset(H^(+))toMn^(2+) Mn^(7+)overset(H_(2)O)toMn^(4+) Mn^(7+)underset(OH^(-))toMn^(6+) QThe number of moles of KMnO_(4) that will be needed to react with one mole of sulphite in an acidic solution is

Volumetric titrations involving KMnO_(4) , are carried out only in presence of dilute H_(2)SO_(4) but not in the presence of HCI or HNO_(3) This is because oxygen produced from KMnO_(4) + dil: H_(2)SO_(4) , is used only for oxidizing the reducing agent. Moreover, H2SO4 does not give any oxygen of its own to oxidize the reducing agent. In case HCI is used, the oxygen produced from KMnO_(4) + HCI is partly used up to oxidize HCI and in case HNO_(3) is used, it itself acts as oxidizing agent and partly oxidizes the reducing agent. KMnO_(4) , in various mediums gives following products Mn^(7+)overset(H^(+))toMn^(2+) Mn^(7+)overset(H_(2)O)toMn^(4+) Mn^(7+)underset(OH^(-))toMn^(6+) Q MnO_(4)^(2-) (1 mole) in neutral medium disproportionates to,

How many mole of FeSO_(4),H_(2)C_(2)O_(4) and FeC_(2)O_(4) are oxidised separately by one mole of KMnO_(4) in acid medium?

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