Which of the compound in each of the following pairs will react faster in `SN^2` reaction with `overset (Ө) O H`
(A) `MeBr (I) and MeI (II)`
(B) `Me_3 C - Cl (III) and MeCl (IV)`
.

Options

A. `overset ((A)) ((I)) overset ((B)) ((III)) overset ((C))((V))`
B. `overset ((A)) ((I)) overset ((B)) ((IV)) overset ((C))((V))`
C. `overset ((A)) ((II)) overset ((B)) ((III)) overset ((C))((VI))`
D. `overset ((A)) ((II)) overset ((B)) ((IV)) overset ((C))((VI))`

Answer

D

Explanation

`(A) (II), I^(Ө)` is a better leaving group than `Br^(Ө)`.
`(B)(V),I^@ RX` undergoes `SN^2` reaction than `3^@ RX`
`(A) (VI)`, Vinyl halide `(V)` does not undergo `SN^1` or `SN^2` reaction , `(VI)` is `1^@ RX`, therefore undergoes `SN^2`.