4-Methyl benzene sulphoic acid reacts with sodium acetate to give :

Options

A.
B.
C.
D.

Explanation

To solve the problem of what 4-methylbenzene sulfonic acid reacts with sodium acetate to give, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The first reactant is 4-methylbenzene sulfonic acid, which has the structure:
- A benzene ring with a methyl group (–CH3) at the para position and a sulfonic acid group (–SO3H) attached.
- The second reactant is sodium acetate (CH3COONa), which consists of an acetate ion (CH3COO-) and sodium ion (Na+).

2. **Understand the Reaction Type**:
- The reaction between a sulfonic acid and a sodium salt (like sodium acetate) typically leads to the formation of a sulfonate salt and an acid.
- In this case, the sulfonic acid will react with the acetate ion.

3. **Write the Reaction**:
- The reaction can be represented as:
\[ \text{4-methylbenzene sulfonic acid} + \text{sodium acetate} \rightarrow \text{4-methylbenzene sulfonate} + \text{acetic acid} \]
- The products formed are:
- 4-methylbenzene sulfonate (C6H4(CH3)(SO3Na))
- Acetic acid (CH3COOH)

4. **Final Product Identification**:
- The final products of the reaction are 4-methylbenzene sulfonate and acetic acid.
- The sulfonate salt retains the structure of the original sulfonic acid but replaces the hydrogen of the sulfonic acid group with sodium.

5. **Conclusion**:
- The correct answer to the question is that 4-methylbenzene sulfonic acid reacts with sodium acetate to give 4-methylbenzene sulfonate and acetic acid.