i. The volume of gases evolved at STP by passing `0.1 A` of current for 965 sec through an aqeous solution of potassium acetate is:
a. `22.4` ml , b. `11.2` ml
c. `89.6` ml , d. `44.8` ml
ii. The mass of gases eveolved in the above problem is:
a. `0.06` gm , b. `0.6` gm
c. `6.0` gm , d. 60 gm
iii. The volume of gases evolved at STP by passing `0.2 A` of current for 965 sec through an aqueous soultion of disodium fumerate is:
a. `22.4` ml , b. `11.2` ml
c. `89.6` ml , d. `44.8` ml

Explanation

`CH_(3)COONa` on Kolbe's electroysis gives 1 mol of `C_(2)H_(6)` (g) and 2 mol of `CO_(2)` (g) per second at anode and 1 mol of `H_(2)` (g) at cathode.
Total moles of gases at cathod and anode = 4 mol
Volume `=4xx22.4` litre at STP
Number of `bar e` involved in the reaction = 2
No. of Faraday = 2F `=2xx96500` C
`t =965` sec and current `=0.1 A`
Charge `=965xx0.1 =96.5 C`
`2F =2xx96500 C implies 4xx22.4` litre of gases
`96.5 C implies (4xx22400 mlxx96.5)/(2xx96500)`
`implies 44.8 ml`
ii. a. Total mass of `C_(2)H_(6) + 2CO_(2) + H_(2) =30+2xx44+2 =120 gm`
`2xx96500 C implies 120 gm` og gases
`96.5 C implies (120xx96.5)/(2xx96500) implies 0.06 gm` ltBrgt iii. c. Disodium fumerate `overset ("Electrolysis") rarr` `HC-=CH+2CO_(2) + H_2)`
`2F =2xx96500 C implies 4 mol xx22.4` liter
`0.2xx965 C implies (4xx22400 ml)/(2xx96500)xx0.2xx965`
`implies 89.6 ml`