`C_(6)H_(12)` (A)`overset (Br_(2)//hv)underset (Monobromination) rarr` One isomer (B)
`C_(6)H_(12)` (C) `overset (Br_(2)//hv)underset (Monobromination) rarr` Number of isomers including geometrical isomers
Both (A) and (C) do not decolourise Baeyer's reagent or `Br_(2)` solution.
Which of the statements is/are correct ?

Options

A. (a) Compound (A) and (B) are, respectively,

B. (b) Compound (C) is
C. (c) The total number of isomers obtained by monobro-mination of (C) is six including geometrical isomer.
D. (d) The major product of monobromination of (C) is

Explanation

To solve the problem, we need to analyze the monobromination of two different compounds, both with the molecular formula \( C_6H_{12} \). Let's denote the first compound as (A) and the second as (C).

### Step-by-step Solution:

1. **Identify Compound (A)**:
- Compound (A) is cyclohexane, which has the formula \( C_6H_{12} \).
- When cyclohexane undergoes monobromination with \( Br_2 \) in the presence of light (hv), it can form one isomer (B) because all carbon atoms in cyclohexane are equivalent. Thus, bromine can attach at any carbon, but the product will be the same regardless of where the bromine is attached.

2. **Identify Compound (C)**:
- Compound (C) is likely to be a branched alkane, such as 2-methylpentane or 3-methylpentane, which also has the formula \( C_6H_{12} \).
- When this compound undergoes monobromination, we need to consider the different positions where bromine can attach and the possibility of forming geometric isomers (cis/trans).

3. **Count Isomers for Compound (C)**:
- For a branched alkane like 2-methylpentane, bromine can attach to different carbon atoms, leading to different structural isomers.
- The possible positions for bromination can yield several unique structures, including cis and trans isomers if there are double bonds or rings present.

4. **Determine the Number of Isomers**:
- After analyzing the potential structures formed from the monobromination of compound (C), we find that there are 6 distinct isomers, including geometric isomers.

5. **Reactions with Baeyer's Reagent and Bromine**:
- Both compounds (A) and (C) do not decolorize Baeyer's reagent or bromine solution, indicating that they do not contain double bonds or other unsaturated functionalities.

6. **Conclusion**:
- The statements regarding the formation of one isomer from (A) and six isomers from (C) including geometric isomers are correct. Therefore, all statements provided in the question are true.

### Summary of Statements:
- Statement about (A) forming one isomer is correct.
- Statement about (C) forming six isomers including geometric isomers is correct.
- Both compounds do not decolorize Baeyer's reagent or bromine solution, confirming they are saturated.

### Final Answer:
All statements regarding compounds (A) and (C) are correct.

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