i. `27.8gm` mixture of alkyne and alkane (both containing same number of carbon atoms) is dissolved in `1000gm` of benzene. The solution freezes at `2.45^@C` (lower than that of benzene). Another `27.8gm` mixture requires `0.6` mol of `H_2` for complete hydrogenation. Calculate the chemical formula of alkyne and alkane (`K_f` for `C_6H_6=4.9`).
ii. Alkyne on hydrogenation with `H_2+Pt` gives the same alkane.
Alkyne does not react with ammoniacal `AgNO_3` solution. Give the structures of both alkyne and alkane.

Explanation

To solve the problem, we will follow these steps:

### Step 1: Define the Chemical Formulas
Let the number of carbon atoms in both the alkyne and alkane be represented by \( n \).
- The formula for the alkyne is \( C_nH_{2n-2} \).
- The formula for the alkane is \( C_nH_{2n+2} \).

### Step 2: Calculate the Molar Masses
...