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There are two paths to prepare compound ...

There are two paths to prepare compound (C).

Which path is feasible and why?

Text Solution

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Path II is feasible since alkynide ion (II) is more nucleophilic than alkynide ion (I) and undergoes `SN^2` reaction with `1^@ RX (BuBr)` to give compound (C), whereas alkynide ion (I) acts as a base and reacts with `3^@` `RX(Me_3C-Br)` and undergoes `E2` elimination reaction to give alkyne `(H-C-=C-Bu)` and alkene
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