In the following sequence of reactions, the products (A) to (G) are formed:
i. `2CH_4(g)overset(Delta)underset(1773K)rarr(A)(g)+B(g)`
ii. `4 mol of (A) overset(Delta)underset(Ni(CN)_4+THF)rarr(C)overset(O_3//o x id.)rarr(D) only`
iii. `(A)overset((1) 1 mol of NaNH_2)underset((2) C_2H_5I)rarr(E)underset(Red hot tube)overset(3 mol of E)rarrunderset((G) only)underset(darr O_3//Red.)F`
Compound F is

Options

A. Mesitylene
B. 1,2,3-Triethylbenzene
C. 1,2,3-Trimethylbenzene
D. 1,3,5-Triethylbenzene

Explanation

To solve the problem step by step, we need to analyze the reactions provided and identify the compounds formed at each stage.

### Step 1: Identify Compound A
The first reaction is:
\[ 2CH_4(g) \overset{\Delta}{\rightarrow} (A)(g) + B(g) \]

When two molecules of methane (CH₄) are heated at high temperatures (1773 K), they undergo a process called pyrolysis, which can lead to the formation of ethane (C₂H₆) and hydrogen gas (H₂). In this case, we can identify:
- **Compound A = C₂H₆ (Ethane)**
- **Compound B = H₂ (Hydrogen)**

### Step 2: Identify Compound E
The third reaction is:
\[ (A) \overset{(1) 1 \text{ mol of NaNH}_2}{\underset{(2) C_2H_5I}{\rightarrow}} E \]

In this step, ethane (C₂H₆) reacts with sodium amide (NaNH₂) and ethyl iodide (C₂H₅I). The sodium amide acts as a strong base and deprotonates ethane to form the ethyl anion (C₂H₅⁻). This anion then reacts with ethyl iodide to form butane (C₄H₁₀).
- **Compound E = C₄H₁₀ (Butane)**

### Step 3: Identify Compound F
The next part of the reaction is:
\[ \text{(Red hot tube)} \overset{3 \text{ mol of E}}{\rightarrow} \underset{(G) \text{ only}}{\rightarrow} F \]

In the red-hot tube, butane (C₄H₁₀) undergoes pyrolysis or cracking, which can lead to the formation of various products, including alkynes. When butane is subjected to strong heating, it can yield ethyne (acetylene, C₂H₂) as one of the products.
- **Compound F = C₂H₂ (Ethyne)**

### Final Answer
Thus, the compound F is **C₂H₂ (Ethyne)**.

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