In the following sequence of reactions, the products (A) to (G) are formed:
i. `2CH_4(g)overset(Delta)underset(1773K)rarr(A)(g)+B(g)`
ii. `4 mol of (A) overset(Delta)underset(Ni(CN)_4+THF)rarr(C)overset(O_3//o x id.)rarr(D) only`
iii. `(A)overset((1) 1 mol of NaNH_2)underset((2) C_2H_5I)rarr(E)underset(Red hot tube)overset(3 mol of E)rarrunderset((G) only)underset(darr O_3//Red.)F`
Compounds G is

Options

A. 2-Oxobutanal
B. 2-Oxobutanoic acid
C. Methylglyoxal
D. 2-Oxopropanoic acid

Explanation

To determine the compound G formed in the sequence of reactions, we will analyze each step systematically.

### Step 1: Identify Compound A
In the first reaction, we have:
\[ 2 CH_4(g) \overset{\Delta}{\rightarrow} (A)(g) + B(g) \]

When two moles of methane (CH₄) are heated to a high temperature (1773 K), they can decompose to form ethyne (C₂H₂) and hydrogen gas. Thus, compound A is:
\[ A = C_2H_2 \text{ (ethyne)} \]

### Step 2: Identify Compound C
Next, we have:
\[ 4 \text{ mol of } (A) \overset{\Delta}{\underset{Ni(CN)_4 + THF}{\rightarrow}} C \]

When ethyne (C₂H₂) is treated with nickel tetracarbonyl (Ni(CN)₄) in tetrahydrofuran (THF), it can undergo a reaction to form a compound that is likely a diene. The exact structure of compound C is not specified, but it is an intermediate formed from the reaction of ethyne.

### Step 3: Identify Compound E
Now, we look at the reaction:
\[ (A) \overset{(1) 1 \text{ mol of } NaNH_2}{\underset{(2) C_2H_5I}{\rightarrow}} E \]

Here, ethyne (C₂H₂) reacts with sodium amide (NaNH₂) to form a carbon anion, which then attacks ethyl iodide (C₂H₅I) in an SN2 reaction. This results in the formation of:
\[ E = CH_3CH_2C \equiv CH \text{ (1-butyne)} \]

### Step 4: Identify Compound F
Next, we have:
\[ \text{(3 mol of E) } \overset{\text{Red hot tube}}{\rightarrow} F \]

When 1-butyne (C₄H₆) is subjected to high temperatures in a red hot tube, it can undergo rearrangement to form a more stable compound, likely leading to:
\[ F = C_6H_6 \text{ (benzene)} \]

### Step 5: Identify Compound G
Finally, we have:
\[ F \overset{O_3 // \text{Red.}}{\rightarrow} G \]

When benzene (C₆H₆) is treated with ozone (O₃) followed by reduction, it typically leads to the formation of carbonyl compounds. In this case, it can yield:
\[ G = 2-oxo butanol \text{ (C₄H₈O₂)} \]

### Conclusion
Thus, the compound G formed in the sequence of reactions is:
\[ G = 2-oxo butanol \]