Compound (A) does not react with Tollens or Grignard reagent, but after treatment with `NaNH_2`, it gives the above test. The compound (A) is/are:

Options

A. (a) `Me--=-Me`
B.
C.
D. (d) `Ph--=-Me`

Explanation

To solve the question, we need to analyze the information provided about compound (A) and its reactions.

### Step-by-Step Solution:

1. **Understanding the Reagents**:
- **Tollens' Reagent**: This reagent is used to test for aldehydes. It does not react with ketones or alkanes. A positive test results in the formation of a silver mirror.
- **Grignard Reagent**: This reagent reacts with compounds that have acidic protons, such as terminal alkynes and aldehydes. It forms a new carbon-carbon bond.

2. **Analyzing Compound (A)**:
- The problem states that compound (A) does not react with either Tollens' or Grignard reagents. This indicates that (A) is likely not an aldehyde or a terminal alkyne, as these would react with the respective reagents.

3. **Treatment with NaNH₂**:
- When compound (A) is treated with sodium amide (NaNH₂), it indicates that (A) is likely an internal alkyne. Internal alkynes do not have acidic protons that can be removed by NaNH₂, but they can be converted to terminal alkynes upon treatment with strong bases like NaNH₂.

4. **Formation of Terminal Alkyne**:
- The treatment of an internal alkyne with NaNH₂ results in the formation of a terminal alkyne. This terminal alkyne can then react positively with both Tollens' reagent and Grignard reagent.

5. **Conclusion**:
- Therefore, compound (A) must be an internal alkyne. Upon treatment with NaNH₂, it converts to a terminal alkyne, which can then react with both Tollens' and Grignard reagents.

### Final Answer:
The compound (A) is an internal alkyne.