`2H--=-Hunderset(NH_4Cl)overset(CuCl)rarrAoverset(H_2+Ni_2B)rarrBunderset((Majo r))overset(Br_2)rarrC`
The major amount of (C) is:

Options

A.
B.
C.
D.

Explanation

To solve the problem step by step, we will analyze the reactions described in the question.

### Step 1: Identify the starting material
We start with 2 moles of acetylene (C2H2).

### Step 2: Reaction with CuCl and NH4Cl
When 2 moles of acetylene react in the presence of CuCl and NH4Cl, they undergo a process known as linear polymerization. This reaction leads to the formation of vinyl acetylene.

**Chemical Reaction:**
\[ 2 \text{C}_2\text{H}_2 \xrightarrow{\text{CuCl, NH}_4\text{Cl}} \text{C}_4\text{H}_4 \text{ (vinyl acetylene)} \]

**Structure of Vinyl Acetylene:**
\[ \text{C} \equiv \text{C}-\text{C}=\text{C}-\text{H} \]

### Step 3: Hydrogenation of Vinyl Acetylene
Next, the vinyl acetylene (A) undergoes hydrogenation in the presence of hydrogen (H2) and a nickel-boron catalyst (Ni2B). This reaction adds hydrogen across the double bond.

**Chemical Reaction:**
\[ \text{C}_4\text{H}_4 + \text{H}_2 \xrightarrow{\text{Ni}_2\text{B}} \text{C}_4\text{H}_6 \text{ (B)} \]

### Step 4: Bromination of the Hydrogenated Product
The product from the hydrogenation (B) is then treated with bromine (Br2). This reaction typically leads to the addition of bromine across the double bond, specifically following Markovnikov's rule, which results in 1,4-addition.

**Chemical Reaction:**
\[ \text{C}_4\text{H}_6 + \text{Br}_2 \rightarrow \text{C}_4\text{H}_6\text{Br}_2 \text{ (C)} \]

### Step 5: Identify the Major Product (C)
The major product (C) formed from the bromination will have the structure where bromine atoms are added at the 1 and 4 positions of the double bond.

**Structure of Major Product (C):**
\[ \text{Br}-\text{C}-\text{C}=\text{C}-\text{Br} \]

### Conclusion
The major product (C) formed from the reactions is a dibromide compound, specifically 1,4-dibromo-2-butene.

### Final Answer
The major amount of (C) is 1,4-dibromo-2-butene.

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