`2HC-=Choverset(Cu^(2+)+O_2)rarr(A)overset(1 mol)underset(HCl)rarr(B)`
Compound (A) and (B) are:

Options

A.
B.
C.
D.

Explanation

To solve the question, we need to identify the compounds (A) and (B) formed during the reactions described. Let's break it down step by step.

### Step 1: Identify the starting material
The starting material is 2 moles of acetylene, which is represented as:
\[ \text{HC} \equiv \text{CH} \]

### Step 2: Understand the reaction conditions
The reaction occurs in the presence of \( \text{Cu}^{2+} \) and \( \text{O}_2 \). This suggests that a dimerization reaction may occur, where two molecules of acetylene combine.

### Step 3: Write the dimerization reaction
When two moles of acetylene react under these conditions, they can form a compound known as 1,3-butadiene:
\[ 2 \text{HC} \equiv \text{CH} \xrightarrow{\text{Cu}^{2+}, \text{O}_2} \text{H}_2C=CH-CH=CH_2 \]

This compound (A) is 1,3-butadiene.

### Step 4: Identify the next reaction
The compound (A) then reacts with 1 mole of HCl. This reaction involves the addition of HCl across the double bonds of 1,3-butadiene.

### Step 5: Write the addition reaction
The addition of HCl to 1,3-butadiene can lead to the formation of a compound known as 1-chlorobutane:
\[ \text{H}_2C=CH-CH=CH_2 + \text{HCl} \rightarrow \text{H}_2C(Cl)-CH=CH_2 \]

This compound (B) is 3-chloro-1-butene.

### Summary of Compounds
- Compound (A): 1,3-butadiene \((\text{H}_2C=CH-CH=CH_2)\)
- Compound (B): 3-chloro-1-butene \((\text{H}_2C(Cl)-CH=CH_2)\)

### Final Answer
- Compound (A) is 1,3-butadiene.
- Compound (B) is 3-chloro-1-butene.