When ethyl ethanoate is treated with excess of `MeMgBr`, followed by hydrolysis, the product is :

Options

A.
B.
C.
D.

Explanation

To solve the question, we need to understand the reaction between ethyl ethanoate and excess methylmagnesium bromide (MeMgBr), followed by hydrolysis. Here’s a step-by-step breakdown of the process:

### Step 1: Identify the Reactants
The reactants in this reaction are:
- Ethyl ethanoate (CH3COC2H5)
- Methylmagnesium bromide (MeMgBr)

### Step 2: First Reaction with MeMgBr
When ethyl ethanoate is treated with excess MeMgBr, the nucleophilic methyl group (CH3-) from MeMgBr attacks the carbonyl carbon (C=O) of ethyl ethanoate. This results in the formation of a tetrahedral intermediate.

**Reaction:**
\[ \text{CH}_3\text{COC}_2\text{H}_5 + \text{MeMgBr} \rightarrow \text{CH}_3\text{C(OMgBr)(C}_2\text{H}_5\text{)}\text{Me} \]

### Step 3: Formation of the Intermediate
The tetrahedral intermediate formed has a magnesium alkoxide group (OMgBr) and the ethyl group remains attached. Since we have excess MeMgBr, this intermediate can react again.

### Step 4: Second Reaction with MeMgBr
The tetrahedral intermediate reacts with another molecule of MeMgBr. The methyl group attacks the carbonyl carbon again, leading to another nucleophilic addition.

**Reaction:**
\[ \text{CH}_3\text{C(OMgBr)(C}_2\text{H}_5\text{)}\text{Me} + \text{MeMgBr} \rightarrow \text{CH}_3\text{C}(\text{C}_2\text{H}_5)(\text{Me})\text{OMgBr} \]

### Step 5: Hydrolysis
After the reaction with excess MeMgBr, the product is hydrolyzed by adding water (H3O+). This step converts the alkoxide (OMgBr) into an alcohol.

**Hydrolysis Reaction:**
\[ \text{CH}_3\text{C}(\text{C}_2\text{H}_5)(\text{Me})\text{OMgBr} + \text{H}_2\text{O} \rightarrow \text{CH}_3\text{C}(\text{C}_2\text{H}_5)(\text{Me})\text{OH} + \text{MgBrOH} \]

### Step 6: Final Product
The final product after hydrolysis is:
\[ \text{CH}_3\text{C}(\text{C}_2\text{H}_5)(\text{Me})\text{OH} \]

This compound is 2-methyl-3-pentanol.

### Conclusion
The product formed when ethyl ethanoate is treated with excess MeMgBr followed by hydrolysis is 2-methyl-3-pentanol.

### Answer
The product is **2-methyl-3-pentanol**.

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