Phenyl isocyanide + Benzyl magnesium bromide `overset(1.Ether Delta) underset(2.H_3 O^(oplus))rarr (A)`. The compound `(A)` is :

Options

A.
B.
C.
D.

Explanation

To solve the problem involving the reaction of phenyl isocyanide with benzyl magnesium bromide, we will follow these steps:

### Step 1: Identify the Reactants
We have two reactants:
- **Phenyl isocyanide**: This can be represented as Ph-N≡C, where Ph is the phenyl group (C6H5).
- **Benzyl magnesium bromide**: This is represented as Ph-CH2-MgBr.

### Step 2: Understand the Reaction Conditions
The reaction occurs in the presence of ether and heat (denoted by Δ). Ether acts as a solvent, and heat facilitates the reaction.

### Step 3: Mechanism of Reaction
1. **Formation of Nucleophile**: The benzyl magnesium bromide dissociates into Ph-CH2⁻ (the nucleophile) and MgBr⁺.
2. **Nucleophilic Attack**: The nucleophile (Ph-CH2⁻) attacks the carbon atom of the isocyanide (N≡C), leading to the formation of a new bond:
- The nitrogen in the isocyanide has a partial positive charge due to the triple bond with carbon, making it susceptible to nucleophilic attack.
- The reaction results in the formation of a compound where the nitrogen is bonded to the phenyl group and the carbon is bonded to the benzyl group.

### Step 4: Formation of Intermediate
The product of the nucleophilic attack will be an intermediate compound that can be represented as:
- Ph-N=C(Ph-CH2)MgBr

### Step 5: Hydrolysis
Upon hydrolysis (the second step in the reaction), the magnesium bromide (MgBr) leaves, and a hydrogen atom replaces it:
- The hydrolysis will yield the final product:
- Ph-NH-C(Ph-CH2)=O (which is an amine).

### Step 6: Identify the Final Product
The final compound (A) can be identified as N-phenyl-1-phenylethylamine, which can be represented structurally as:
- N-phenyl-1-phenylethanamine

### Conclusion
Thus, the compound (A) is N-phenyl-1-phenylethanamine.

### Answer
The compound (A) is N-phenyl-1-phenylethanamine.