The compound `(A)` in the previous question is further hydrolysed in dilute acidic medium to give compounds `(B)` and `( C)`. The compounds `(B)` and `( C)` are :

Options

A. `PhNH_2` and `PhCH=O`
B. `PhCH_2 NH_2` and `PhCH=O`
C. `PhNH_2` and `PhCH_2 CH=O`
D. `PhCH_2 NH_2` and `PhCH_2 CH=O`.

Explanation

To solve the question regarding the hydrolysis of compound (A) in a dilute acidic medium to yield compounds (B) and (C), we can follow these steps:

### Step-by-Step Solution:

1. **Identify Compound (A)**:
- From the previous context, compound (A) is identified as a compound with a phenyl group and a double bond, specifically, it can be represented as phenyl-CH=CH2 (styrene).

2. **Understanding Hydrolysis**:
- Hydrolysis in a dilute acidic medium typically involves the addition of water (H2O) across the double bond. The acidic medium (H3O+) facilitates the reaction by providing protons.

3. **Breaking the Double Bond**:
- The double bond in compound (A) will undergo hydrolysis. The reaction involves the addition of H2O across the double bond. This means that one carbon will bond with a hydroxyl group (-OH) and the other will bond with a hydrogen atom (H).

4. **Formation of Compounds (B) and (C)**:
- Upon hydrolysis, the compound will yield:
- **Compound (B)**: Aniline (C6H5NH2) - This is formed from the nitrogen in the phenyl group.
- **Compound (C)**: Benzaldehyde (C6H5CHO) - This is formed from the remaining part of the molecule after the hydrolysis.

5. **Final Compounds**:
- Thus, the final compounds after hydrolysis are:
- (B) Aniline (C6H5NH2)
- (C) Benzaldehyde (C6H5CHO)

### Final Answer:
- The compounds (B) and (C) are Aniline (C6H5NH2) and Benzaldehyde (C6H5CHO), respectively.