Compound (A), `C_(8)H_(6)NOBr`, is optically active. Reduction of (A) gives (B) which reacts with nitrouos acid to form (C), dihydric alcohol. Benzene sulphonyl chloride reacts with (B) to give a product soluble in NaOH. Hydrolysis of (A) gives (D) which is an optically active acid. (A) does not give any precipitate with aqueous `AgNO_(3)` . Controlled oxidation of (A) gives monobromo benzoic acid. Compound (A) on reaction with `Br_(2)//Fe` gives only one compound. Identify (A), (B), (C), and (D).

Explanation

To solve the question step by step, we will identify the compounds A, B, C, and D based on the information provided.

### Step 1: Analyze Compound A
Given the molecular formula of compound A as `C8H6NOBr`, we calculate the degree of unsaturation (DU) to understand its structure.

**Degree of Unsaturation Calculation:**
Using the formula:
\[ \text{DU} = \frac{(2n_C + 2 - n_H + n_X - n_N)}{2} \]
...