An aromatic compound (A), `C_(7)H_(5)NO_(2)CI_(2)` on reduction with `Sn//HCI` gives (G), which on reaction with `NaNO_(2)//HCI` gives (B). Compound (B) does not form a dye with `beta`-naphthol. However, (B) gives red colour with ceric ammonium nitrate and on oxidation gives an acid (D) of equivalent weight 191. Decarboxylation of (D) gives (E), which forms a mono nitro derivative (F) on nitrotion. Give the structures of (A) to (F) with proper reasoning.

Explanation

To solve the problem step by step, we will analyze the information provided and deduce the structures of compounds (A) to (F).

### Step 1: Determine the structure of compound (A)
Given the molecular formula of compound (A) is `C7H5NO2Cl2`, we first calculate the degree of unsaturation.

**Degree of Unsaturation Calculation:**
Using the formula:
\[ \text{Degree of Unsaturation} = \frac{(2n + 2 - n_H - n_X - n_N)}{2} \]
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