When ethanol is heated with conc. `H_(2)SO_(4)` at `140^(@)C` (431K), the product obtained is:

Options

A. Diethyl sulphate
B. Ethene
C. Diethyl ether
D. All

Explanation

To determine the product obtained when ethanol is heated with concentrated sulfuric acid (H₂SO₄) at 140°C, we can follow these steps:

### Step 1: Understand the Reactants
Ethanol (C₂H₅OH) is an alcohol, and concentrated sulfuric acid (H₂SO₄) is a strong dehydrating agent. When alcohols are treated with concentrated sulfuric acid, they undergo dehydration reactions.

**Hint:** Identify the reactants involved in the reaction.

### Step 2: Identify the Reaction Conditions
The temperature at which the reaction occurs is crucial. In this case, the temperature is 140°C (431 K). The temperature influences the type of product formed during the reaction.

**Hint:** Note how temperature can affect the outcome of chemical reactions.

### Step 3: Predict the Reaction at 140°C
At 140°C, ethanol reacts with concentrated sulfuric acid to undergo dehydration and form diethyl ether (C₂H₅)₂O. This is a result of the elimination of water (H₂O) from two ethanol molecules.

**Hint:** Consider what happens to the ethanol molecules when they lose water.

### Step 4: Write the Chemical Equation
The reaction can be represented as follows:
\[ 2 \text{C}_2\text{H}_5\text{OH} \xrightarrow{\text{H}_2\text{SO}_4, 140°C} (\text{C}_2\text{H}_5)_2\text{O} + \text{H}_2\text{O} \]

**Hint:** Formulate the balanced equation for the reaction.

### Step 5: Conclusion
The product formed when ethanol is heated with concentrated sulfuric acid at 140°C is diethyl ether.

**Final Answer:** Diethyl ether (C₂H₅)₂O.