`CH_(3)OH+C_(2)H_(5)OH overset(H^(o+))rarr` Products

Options

A. The product is `CH_(3)-O-C_(2)H_(5)`.
B. The product is `CH_(3)-O-CH_(3)`.
C. The product is `C_(2)H_(5)-O-C_(2)H_(5)`.
D. All

Explanation

To solve the question regarding the reaction between methanol (CH₃OH) and ethanol (C₂H₅OH) in the presence of H⁺, we will follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
The reactants are methanol (CH₃OH) and ethanol (C₂H₅OH).

2. **Understand the Reaction Type**:
The reaction involves the intermolecular dehydration of two different one-degree alcohols. This means that the alcohols will react to form ethers.

3. **Write the General Reaction**:
The general reaction for the formation of ethers from alcohols can be represented as:
\[ R_1OH + R_2OH \xrightarrow{H^+} R_1OR_2 + H_2O \]
where \(R_1\) and \(R_2\) are the alkyl groups from the alcohols.

4. **Identify the Possible Products**:
In this case, the possible products from the reaction of methanol and ethanol are:
- Dimethyl ether (from two methanol molecules): CH₃OCH₃
- Ethyl methyl ether (from one methanol and one ethanol): CH₃OCH₂CH₃
- Diethyl ether (from two ethanol molecules): C₂H₅OC₂H₅

5. **List the Products**:
Therefore, the products formed from the reaction are:
- CH₃OCH₃ (Dimethyl ether)
- CH₃OCH₂CH₃ (Ethyl methyl ether)
- C₂H₅OC₂H₅ (Diethyl ether)

6. **Conclusion**:
Since all three ethers can be formed from the reaction of methanol and ethanol in the presence of an acid catalyst, the correct answer is that all three products are formed.

### Final Answer:
The products of the reaction CH₃OH + C₂H₅OH in the presence of H⁺ are a mixture of ethers: CH₃OCH₃, CH₃OCH₂CH₃, and C₂H₅OC₂H₅.