In `CH_(3)CH_(2)OH`, the bond that undegoes heterolytic clevage most readily is:

Options

A. C-C
B. C-O
C. C-H
D. O-H

Explanation

To determine which bond in ethanol (CH₃CH₂OH) undergoes heterolytic cleavage most readily, we will analyze the types of bonds present in the molecule and their characteristics.

### Step-by-Step Solution:

1. **Identify the Bonds in Ethanol**:
Ethanol (CH₃CH₂OH) contains several types of bonds:
- C-C bond (between the two carbon atoms)
- C-O bond (between the carbon and the oxygen)
- O-H bond (between the oxygen and the hydrogen)
- C-H bonds (between the carbon and hydrogen atoms)

2. **Assess the Polarity of Each Bond**:
- **C-C Bond**: This bond is between two carbon atoms, which have similar electronegativities. Therefore, it is non-polar and not prone to heterolytic cleavage.
- **C-O Bond**: This bond is polar because oxygen is more electronegative than carbon. However, it is not the most polar bond in the molecule.
- **O-H Bond**: This bond is highly polar because oxygen is significantly more electronegative than hydrogen. The electron density is pulled towards the oxygen atom, making it more susceptible to cleavage.
- **C-H Bonds**: These bonds are relatively non-polar as carbon and hydrogen have similar electronegativities.

3. **Determine the Most Readily Cleaved Bond**:
Among the bonds analyzed, the O-H bond is the most polar and has a significant difference in electronegativity between oxygen and hydrogen. This makes the O-H bond more susceptible to heterolytic cleavage, where the bond breaks and both electrons are taken by one of the atoms (in this case, the oxygen).

4. **Conclusion**:
Therefore, in ethanol (CH₃CH₂OH), the bond that undergoes heterolytic cleavage most readily is the **O-H bond**.