An optically active alcohol A `(C_(6)H_(10)O)` absorbs 2 mol of hydrogen per mole of A upon catalytic hydrogenation and gives a product B. The compound B is resistant to oxidation by `CrO_(3)` and does not show any optical activity Deduce the structures of A and B.

Explanation

To deduce the structures of the optically active alcohol A (C₆H₁₀O) and the product B, we can follow these steps:

### Step 1: Analyze the Given Information
- Alcohol A is optically active, meaning it has a chiral center.
- It absorbs 2 moles of hydrogen upon catalytic hydrogenation.
- The product B is resistant to oxidation by CrO₃ and does not show optical activity.

### Step 2: Determine the Degree of Unsaturation
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