Write the product when Chlorine gas is passed through H2S.

Explanation

To determine the product when chlorine gas is passed through hydrogen sulfide (H2S), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants in this reaction are hydrogen sulfide (H2S) and chlorine gas (Cl2).

2. **Understand the Reaction**:
- Chlorine is a more reactive element compared to sulfur. When chlorine gas is introduced to hydrogen sulfide, a chemical reaction occurs where chlorine displaces sulfur.

3. **Write the Reaction**:
- The reaction can be represented as:
\[ H_2S + Cl_2 \rightarrow S + HCl \]
- Here, sulfur (S) is formed along with hydrochloric acid (HCl).

4. **Balance the Reaction**:
- To balance the equation, we need to ensure that the number of atoms for each element is the same on both sides. The balanced equation is:
\[ H_2S + Cl_2 \rightarrow S + 2HCl \]
- This shows that one molecule of hydrogen sulfide reacts with one molecule of chlorine gas to produce one molecule of sulfur and two molecules of hydrochloric acid.

5. **Identify the Type of Reaction**:
- This reaction is a redox reaction, where oxidation and reduction occur simultaneously. In this case:
- Hydrogen in H2S is oxidized to form sulfur (loss of hydrogen).
- Chlorine is reduced to form hydrochloric acid (gain of hydrogen).

### Final Products:
- The final products of the reaction are:
- Sulfur (S)
- Hydrochloric acid (HCl)