The boiling points of ethyl acetate and `CH_3 OH`, respectively, are `77^@ C` and `65^@ C`. Which of the following reactions can be shifted to the right by the distillation of the reaction mixture at about `66^@ C`.
(I) `MeCOOEt + MeOH rarr`
(II) `MeCOOMe + EtOH rarr`
(III) `MeCOOMe + PhOH rarr`
(IV) `MeCOOPh + MeOH rarr`.

Options

A. `(I),(II)`
B. `(II), (III)`
C. `(I),(III)`
D. `(II),(IV)`

Explanation

To determine which reactions can be shifted to the right by distillation of the reaction mixture at about 66°C, we need to analyze the given reactions in relation to the boiling points of the reactants and products.

### Step-by-Step Solution:

1. **Identify the boiling points**:
- The boiling point of methanol (CH₃OH) is 65°C.
- The boiling point of ethyl acetate (MeCOOEt) is 77°C.

2. **Analyze Reaction (I)**:
- Reaction: MeCOOEt + MeOH → Products
- The products formed will be MeCOOMe (methyl acetate) and ethanol (EtOH).
- Since methanol has a boiling point of 65°C, it will evaporate at 66°C, removing it from the reaction mixture.
- According to Le Chatelier's principle, removing a reactant (methanol) will shift the equilibrium to the right, favoring product formation.

3. **Analyze Reaction (II)**:
- Reaction: MeCOOMe + EtOH → Products
- The products formed will be MeCOOEt (ethyl acetate) and methanol.
- Again, since methanol has a boiling point of 65°C, it will evaporate at 66°C, thus shifting the equilibrium to the right.

4. **Analyze Reaction (III)**:
- Reaction: MeCOOMe + PhOH → Products
- The products formed will be MeCOOPh (phenyl acetate) and methanol.
- We cannot determine the boiling points of the products (MeCOOPh and MeCOOMe) or phenol (PhOH) from the information given, so we cannot conclude if the reaction can be shifted to the right.

5. **Analyze Reaction (IV)**:
- Reaction: MeCOOPh + MeOH → Products
- The products formed will be MeCOOMe (methyl acetate) and phenol.
- Similar to the previous reaction, we cannot determine the boiling points of the products or phenol, so we cannot conclude if the reaction can be shifted to the right.

### Conclusion:
From the analysis, reactions (I) and (II) can be shifted to the right by distillation at about 66°C because methanol, a reactant in both reactions, will evaporate. Reactions (III) and (IV) cannot be conclusively determined due to lack of boiling point information.

Therefore, the correct answer is:
**Reactions (I) and (II) can be shifted to the right by distillation at about 66°C.**