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(KOOC-CH=CH-COOK) undergoes Kolbe's reac...

`(KOOC-CH=CH-COOK)` undergoes Kolbe's reaction to form a product which reacts with ammoniacal `AgNO_3` solution to form a precipitate.
The product is a saturated hydrocarbon that forms salt with `AgNO_3`.

A

If both `(A)` are `( R)` are true and `( R)` is the correct explanation of `(A)`.

B

If both `(A)` and `( R)` are true but `( R)` is not the correct explanation of `(A)`.

C

If `(A)` is true but `( R)` is false.

D

If `(A)` is false but `( R)` is true.

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To solve the given question step by step, we will analyze the reaction of the compound `(KOOC-CH=CH-COOK)` (potassium salt of a carboxylic acid) undergoing Kolbe's electrolysis reaction and its subsequent reaction with ammoniacal `AgNO3`. ### Step 1: Identify the Compound The compound given is `(KOOC-CH=CH-COOK)`, which is the potassium salt of 2-butenoic acid. This compound has two carboxylate groups (–COOK). ### Step 2: Kolbe's Electrolysis Reaction In Kolbe's electrolysis, the carboxylate ions (from the two carboxylic acid groups) are oxidized at the anode. The reaction can be summarized as follows: - Each carboxylate ion will lose a carbon dioxide molecule (CO2) and will couple to form a new carbon-carbon bond. For the given compound, the reaction will produce: - 2 moles of CO2 (one from each carboxylate group). - A product that is an alkyne (since the original compound has a double bond). ### Step 3: Determine the Product The product formed from the Kolbe's electrolysis of `(KOOC-CH=CH-COOK)` will be an alkyne. Specifically, it will be 1-butyne (CH≡C-CH2-COOH) after the loss of CO2. ### Step 4: Reaction with Ammoniacal AgNO3 The product formed (1-butyne) can react with ammoniacal `AgNO3`, which is known as Tollens' reagent. This reagent is used to test for terminal alkynes. The reaction will lead to the formation of a silver acetylide precipitate. ### Step 5: Conclusion The assertion states that the product is a saturated hydrocarbon that forms a salt with `AgNO3`. However, since the product is an alkyne (which is an unsaturated hydrocarbon), the assertion is correct, but the reason is incorrect. Therefore, the correct answer is option C: Assertion is correct, reason is wrong.

To solve the given question step by step, we will analyze the reaction of the compound `(KOOC-CH=CH-COOK)` (potassium salt of a carboxylic acid) undergoing Kolbe's electrolysis reaction and its subsequent reaction with ammoniacal `AgNO3`. ### Step 1: Identify the Compound The compound given is `(KOOC-CH=CH-COOK)`, which is the potassium salt of 2-butenoic acid. This compound has two carboxylate groups (–COOK). ### Step 2: Kolbe's Electrolysis Reaction In Kolbe's electrolysis, the carboxylate ions (from the two carboxylic acid groups) are oxidized at the anode. The reaction can be summarized as follows: - Each carboxylate ion will lose a carbon dioxide molecule (CO2) and will couple to form a new carbon-carbon bond. ...
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