Acetic acid on reaction with hydrazoic acid `(N_3 H)` in the presence of `H_2 SO_4` followed by heating and hydrolysis in basic medium gives acetamide.
Methyl isocyanate `(Me-N=C=O)` is formed is an intermediate compound.

Options

A. If both `(A)` are `( R)` are true and `( R)` is the correct explanation of `(A)`.
B. If both `(A)` and `( R)` are true but `( R)` is not the correct explanation of `(A)`.
C. If `(A)` is true but `( R)` is false.
D. If `(A)` is false but `( R)` is true.

Explanation

To solve the problem, we will break down the reaction of acetic acid with hydrazoic acid in the presence of sulfuric acid, followed by heating and hydrolysis in a basic medium, to understand how acetamide is formed and the role of methyl isocyanate as an intermediate.

### Step-by-Step Solution:

1. **Identify the Reactants**:
- Acetic acid (CH₃COOH)
- Hydrazoic acid (N₃H)
- Sulfuric acid (H₂SO₄)

2. **Initial Reaction**:
- When acetic acid reacts with hydrazoic acid in the presence of sulfuric acid, a dehydration reaction occurs. The hydroxyl group (OH) from acetic acid and a hydrogen atom from hydrazoic acid combine to form water (H₂O), leading to the formation of an intermediate compound.

3. **Formation of the Intermediate**:
- The reaction can be represented as:
\[ \text{CH}_3\text{COOH} + \text{N}_3\text{H} \rightarrow \text{CH}_3\text{C}(=O)\text{N}_3 + \text{H}_2\text{O} \]
- The product formed is an azide derivative of acetic acid.

4. **Elimination of Nitrogen**:
- The azide group (N₃) is unstable and can decompose, releasing nitrogen gas (N₂) and forming methyl isocyanate (Me-N=C=O) as an intermediate:
\[ \text{CH}_3\text{C}(=O)\text{N}_3 \rightarrow \text{CH}_3\text{N=C=O} + \text{N}_2 \]

5. **Hydrolysis of Methyl Isocyanate**:
- The next step involves hydrolysis of methyl isocyanate in a basic medium. During hydrolysis, the isocyanate group reacts with water:
\[ \text{CH}_3\text{N=C=O} + \text{H}_2\text{O} \rightarrow \text{CH}_3\text{NH}_2 + \text{CO}_2 \]
- This reaction yields acetamide (CH₃NH₂) and carbon dioxide (CO₂).

6. **Final Products**:
- The final products of the reaction are acetamide and carbon dioxide.

7. **Conclusion**:
- The assertion that acetic acid reacts with hydrazoic acid to give acetamide is incorrect, as the final product is methyl amine (CH₃NH₂) and carbon dioxide (CO₂). The reason that methyl isocyanate is formed as an intermediate is correct.

### Summary of the Assertion and Reason:
- **Assertion**: Acetic acid on reaction with hydrazoic acid in the presence of sulfuric acid followed by heating and hydrolysis in a basic medium gives acetamide. **(Incorrect)**
- **Reason**: Methyl isocyanate is formed as an intermediate compound. **(Correct)**

### Answer:
The correct option is D: Assertion is wrong, reason is correct.