An organic compound `(A)` on treatment with acetic acid in the presence of sulphuric acid produces an ester `(B)`. `(A)` on mild oxidation gives `( C), ( C)` with `50 %` potassium hydroxide followed by acidification with dilute hydroxide acid generates `(A)` and `(D) ,(D)` with phosphorus pentachloride followed by reaction with ammonia gives `(E) , (E)` on dehydration produces hydrocyanic acid. Identify the compounds `(A), (B), (C), (D)`, and `(E)`.

Explanation

To solve the problem step by step, we will identify each compound `(A)`, `(B)`, `(C)`, `(D)`, and `(E)` based on the reactions described.

### Step 1: Identify Compound `(A)`
The question states that an organic compound `(A)` on treatment with acetic acid in the presence of sulfuric acid produces an ester `(B)`. This suggests that `(A)` is likely an alcohol, as alcohols react with carboxylic acids to form esters.

**Assumption**: Let’s assume `(A)` is methanol (CH₃OH).

### Step 2: Identify Compound `(B)`
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