Ethanamine is treated with nitrous acid at ordinary temperature, the products will be:

Options

A. Ethanol only
B. ethanol acetic acid, `N_2`, and `H_2O`
C. Acetic acid, ethane, and `H_2O`
D. Ethanol, ethene, `N_2` and`H_2O`

Explanation

To solve the problem of what products are formed when ethanamine (C2H5NH2) is treated with nitrous acid (HNO2) at ordinary temperature, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactant is ethanamine (C2H5NH2) and nitrous acid (HNO2).

2. **Understand the Reaction Conditions**:
- The reaction occurs at ordinary temperatures, typically between 0 to 5 degrees Celsius.

3. **Formation of Diazonium Salt**:
- When ethanamine is treated with nitrous acid, it first forms a diazonium salt. The reaction can be represented as:
\[ C2H5NH2 + HNO2 \rightarrow C2H5N2^+Cl^- + H2O \]
- Here, the ethanamine reacts with nitrous acid to form ethyl diazonium chloride.

4. **Decomposition of Diazonium Salt**:
- The diazonium salt is unstable and decomposes to form various products. The decomposition can be represented as:
\[ C2H5N2^+Cl^- \rightarrow C2H5OH + CH2=CH2 + N2 + H2O \]
- This indicates that the diazonium salt decomposes to yield ethanol (C2H5OH), ethene (CH2=CH2), nitrogen gas (N2), and water (H2O).

5. **Identify the Final Products**:
- The final products of the reaction are ethanol, ethene, nitrogen gas, and water.

6. **Select the Correct Option**:
- Based on the products formed, the correct answer is option D: Ethanol, Ethene, N2, and H2O.

### Summary of Products:
- Ethanol (C2H5OH)
- Ethene (CH2=CH2)
- Nitrogen gas (N2)
- Water (H2O)

### Final Answer:
The products formed when ethanamine is treated with nitrous acid at ordinary temperature are: **Ethanol, Ethene, N2, and H2O** (Option D).

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