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Pick up the correct stament :

A

The boling points of alkly halides are more than those of the corresponding alkances .

B

In water , the solulity of ` CH_3OH gt C_2H_5OH gt C_6H_5OH`.

C

`C_6H_5NH_2` is a weaker base thann ` NH_3`.

D

All the above statements are correct .

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The correct Answer is:
To solve the question of identifying the correct statement regarding organic compounds, we will analyze each statement step by step. ### Step 1: Analyze the first statement **Statement 1**: The boiling point of alkyl halides is more than those of corresponding alkenes. - **Explanation**: Alkyl halides are polar molecules due to the electronegativity difference between carbon and halogen atoms. This polarity leads to dipole-dipole interactions, which increase the boiling point. In contrast, alkenes are non-polar and primarily exhibit London dispersion forces, which are weaker than dipole-dipole interactions. Therefore, alkyl halides have higher boiling points than corresponding alkenes. **Conclusion**: This statement is correct. ### Step 2: Analyze the second statement **Statement 2**: The solubility of alcohols in water depends on steric hindrance. - **Explanation**: Solubility in water is influenced by hydrogen bonding. Alcohols can form hydrogen bonds with water, and the extent of this ability is affected by steric hindrance. The order of steric hindrance is CH3OH (methanol) < C2H5OH (ethanol) < C6H5OH (phenol). Since methanol has the least steric hindrance, it is the most soluble in water, while phenol, with the most steric hindrance, is the least soluble. **Conclusion**: This statement is correct. ### Step 3: Analyze the third statement **Statement 3**: Aniline is a weaker base than NH3 (ammonia). - **Explanation**: Aniline (C6H5NH2) has a lone pair of electrons on the nitrogen atom that participates in resonance with the aromatic ring. This delocalization of the lone pair reduces its availability for protonation, making aniline a weaker base compared to ammonia, which has a lone pair that is not involved in resonance and can be easily donated. **Conclusion**: This statement is correct. ### Final Conclusion Since all three statements are correct, the answer to the question is: **Answer**: Option D (All statements are correct).

To solve the question of identifying the correct statement regarding organic compounds, we will analyze each statement step by step. ### Step 1: Analyze the first statement **Statement 1**: The boiling point of alkyl halides is more than those of corresponding alkenes. - **Explanation**: Alkyl halides are polar molecules due to the electronegativity difference between carbon and halogen atoms. This polarity leads to dipole-dipole interactions, which increase the boiling point. In contrast, alkenes are non-polar and primarily exhibit London dispersion forces, which are weaker than dipole-dipole interactions. Therefore, alkyl halides have higher boiling points than corresponding alkenes. **Conclusion**: This statement is correct. ...
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CENGAGE CHEMISTRY ENGLISH-ORGANIC COMPOUNDS WITH FUNCTIONAL GROUP-Exercises Single Correct
  1. Which of the following is formed when RNH2 reacts with RCHO?

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  2. Which of the following represents the poinsonous gas which caused the ...

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  3. The conjugate base of (CH3) NH2^(o+) is :

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  4. Which of the following is the weakest base ?

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  5. Which of the following reaction does not yield amine?

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  6. Primary and secondary amines are distinguished by :

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  7. Indicate which nitrogen compound amongst the following would undergo H...

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  8. Pick up the correct stament :

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  9. The producet of the reaction of alcoholic silver nitrite with ethyl br...

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  10. The electrolytic reduction of nitrobenzene in strongly acidic medium p...

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  11. Azoxybenzene can be obtained by the treatment of mitro-benzene with :

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  12. Tertiary nitro compounds cannot show tautomerism becauses :

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  13. Diazo coupling is useful to prepare some

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  14. The following reaction constituts : RNH2 + S=C=S overset (HgCl2) (r...

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  15. Primary , secondary , tertiary amines can be separated by the followin...

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  16. When C6 H5N2Cl is reduced with Na 2 SnOO2, the product is :

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  17. Nitrogen is likely to be evolved when NaNO2 in dilute HCl warmed with...

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  18. A compound X has the molecular formula C(7)H(7)NO. On treatment with B...

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  19. A compound (X) has the molecular formula C3 H7 NO . With Br2 and KO...

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  20. An amine on treatment with HNO2 evolved N2 The amine on exhaustive me...

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