The producet of the reaction of alcoholic silver nitrite with ethyl bromide is :

Options

A. Ethane nitrile
B. Ethene
C. Nitroethane
D. Ethyl alcohol

Explanation

To determine the product of the reaction between alcoholic silver nitrate (AgNO3) and ethyl bromide (C2H5Br), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants in this reaction are alcoholic silver nitrate (AgNO3) and ethyl bromide (C2H5Br).

2. **Understand the Nature of the Reaction**:
- Alcoholic silver nitrate is a source of Ag+ ions in an alcoholic medium. Ethyl bromide is an alkyl halide that can undergo nucleophilic substitution reactions.

3. **Nucleophilic Substitution Mechanism**:
- In this reaction, the Ag+ ion from silver nitrate will react with the bromide ion (Br-) from ethyl bromide. The Ag+ ion will effectively "trap" the Br- ion, leading to the formation of a precipitate of silver bromide (AgBr).

4. **Formation of Products**:
- The ethyl group (C2H5) will be left with a nitro group (NO2) after the bromide has been displaced. This leads to the formation of nitroethane (C2H5NO2).

5. **Write the Balanced Reaction**:
- The overall reaction can be summarized as:
\[ \text{AgNO}_3 + \text{C}_2\text{H}_5\text{Br} \rightarrow \text{C}_2\text{H}_5\text{NO}_2 + \text{AgBr} \]
- Here, AgBr is formed as a yellow precipitate.

6. **Conclusion**:
- The product of the reaction is nitroethane (C2H5NO2).

### Final Answer:
The product of the reaction of alcoholic silver nitrate with ethyl bromide is nitroethane (C2H5NO2).

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