When ` C_6 H_5N_2Cl` is reduced with ` Na _2 SnOO_2`, the product is :

Options

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Explanation

To solve the question of what product is formed when C6H5N2Cl is reduced with Na2SnO2, we can follow these steps:

### Step 1: Identify the Reactants
The compound C6H5N2Cl is known as benzenediazonium chloride. It consists of a benzene ring (C6H5) with a diazonium group (N2+) and a chloride ion (Cl-).

**Hint:** Recognize the structure of benzenediazonium chloride and its functional groups.

### Step 2: Understand the Reduction Process
The reduction of benzenediazonium chloride can occur through various reducing agents. In this case, we are using sodium stannite (Na2SnO2). This reducing agent can convert the diazonium group (N2+) into a hydrogen atom (H) by replacing it.

**Hint:** Remember that reducing agents often convert functional groups into less oxidized forms.

### Step 3: Write the Reaction
When benzenediazonium chloride is treated with Na2SnO2, the diazonium group is reduced to a hydrogen atom, and the chloride ion remains unchanged. The reaction can be summarized as follows:

C6H5N2Cl + Na2SnO2 → C6H6 + NaCl + N2

Here, C6H6 represents benzene, which is the product of the reduction.

**Hint:** Focus on the transformation of the diazonium group into a hydrogen atom.

### Step 4: Identify the Product
The final product of this reaction is benzene (C6H6). The chloride ion (Cl-) and nitrogen gas (N2) are byproducts of the reaction.

**Hint:** Always confirm the final product by checking the molecular formula.

### Conclusion
When C6H5N2Cl is reduced with Na2SnO2, the product formed is benzene (C6H6).

**Final Answer:** Benzene (C6H6)

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