A compound (X) has the molecular formula ` C_3 H_7 NO` . With ` Br_2` and ` KOH`, (X) gives (Y) . (Y) responds to mustard oil reaction . (Y) upon treatment with ` HNO_2` evolves `N_2` and gives an alcohol (Z) which gives iodoform test , (X) is likelty to be :

Options

A. `C_2H_5CONH_2`
B. `CH_3COHH_2`
C. `CH_3COONH_4`
D. `C_2H_5CNO`

Explanation

To solve the problem step-by-step, we need to analyze the information given and deduce the structure of compound (X) based on its reactions and properties.

### Step 1: Identify the molecular formula and possible structures
The molecular formula of compound (X) is C₃H₇NO. This indicates that (X) could be an amide, amine, or another nitrogen-containing organic compound. Given that it reacts with Br₂ and KOH, we can infer that it is likely an amide.

**Hint:** Look for functional groups that match the molecular formula and consider common reactions involving nitrogen compounds.

### Step 2: Reaction with Br₂ and KOH
The reaction of (X) with Br₂ and KOH suggests a Hofmann degradation reaction, which typically involves the conversion of an amide to a primary amine with one less carbon atom. Thus, if (X) is an amide, it will yield a primary amine (Y).

**Hint:** Recall that Hofmann degradation reduces the carbon chain by one carbon atom and produces a primary amine.

### Step 3: Determine the structure of (X)
Since (X) is likely an amide and has three carbons, the most plausible structure is propanamide (C₂H₅CONH₂). This structure fits the molecular formula C₃H₇NO.

**Hint:** Consider the simplest amide structures that fit the molecular formula.

### Step 4: Identify compound (Y)
Upon Hofmann degradation, propanamide (X) will yield ethylamine (C₂H₅NH₂) as compound (Y). Ethylamine is a primary amine, which is consistent with the mustard oil reaction.

**Hint:** Primary amines react with carbon disulfide to give isothiocyanates, which have a characteristic odor.

### Step 5: Reaction of (Y) with HNO₂
When ethylamine (Y) is treated with nitrous acid (HNO₂), it produces ethanol (Z) and nitrogen gas (N₂). This reaction is characteristic of primary amines.

**Hint:** Remember that primary amines react with nitrous acid to form alcohols and nitrogen gas.

### Step 6: Identify compound (Z)
Ethanol (C₂H₅OH) is the alcohol produced (Z) from the reaction of ethylamine with HNO₂. Ethanol is known to give a positive iodoform test, which is another clue confirming our findings.

**Hint:** The iodoform test is positive for alcohols with the structure R-CO-CH₃.

### Conclusion
Based on the deductions made through the steps, we can conclude that compound (X) is propanamide (C₂H₅CONH₂).

**Final Answer:** (X) is likely to be propanamide.