Home
Class 12
CHEMISTRY
Statement I: Aniline on reaction with N...

Statement I: Aniline on reaction with ` NaNO_2 HCl` at `0^@C` followed by coupling with `beta`-naphthol gives a dark blue coloured precipitate.
Statement II: The colour of the compound formed in the reaction of aniline with `NaNO_2//HCl` at ` 0^@C` followed by coupling with `beta`-naphthol is due to extended conjugation.

A

Statement (I) is true : Statement (II) is true : Statement (II) is the correct esplanation of Statement (I)

B

Statement (I) is true : Statement (II) is true , Statement (II) is not the correct exphanation fo sTatement (I)

C

Statement I is True, Statament II is false

D

Statement (I) is false , Statement (II) is true .

Text Solution

AI Generated Solution

The correct Answer is:
To analyze the given statements, let's break down the reactions and concepts involved step by step. ### Step 1: Understanding the Reaction of Aniline with NaNO2 and HCl Aniline (C6H5NH2) reacts with sodium nitrite (NaNO2) in the presence of hydrochloric acid (HCl) at low temperatures (0°C to 5°C). This reaction leads to the formation of benzene diazonium chloride (C6H5N2Cl). **Hint:** Remember that diazonium salts are formed from primary amines in acidic conditions. ### Step 2: Formation of Benzene Diazonium Chloride The reaction can be summarized as follows: \[ \text{C6H5NH2} + \text{NaNO2} + \text{HCl} \rightarrow \text{C6H5N2Cl} + \text{NaCl} + \text{H2O} \] Here, aniline is converted to benzene diazonium chloride, which is a key intermediate in azo coupling reactions. **Hint:** Focus on the role of sodium nitrite and HCl in converting aniline to a diazonium compound. ### Step 3: Coupling with Beta-Naphthol Next, the benzene diazonium chloride reacts with beta-naphthol (C10H7OH). This reaction occurs at low temperatures and results in the formation of an azo dye. The coupling reaction can be represented as: \[ \text{C6H5N2Cl} + \text{C10H7OH} \rightarrow \text{C6H5N=N-C10H7OH} + \text{HCl} \] This forms an azo compound, which typically has a vivid color due to the presence of the azo (-N=N-) linkage. **Hint:** Azo coupling reactions often produce colored compounds due to the extended conjugation of π-electrons. ### Step 4: Color of the Azo Compound The resulting azo compound from the coupling of benzene diazonium chloride with beta-naphthol is known to be orange-red in color, not dark blue as stated in Statement I. The color arises from the extended conjugation in the molecule, which allows for the absorption of visible light. **Hint:** Recall that the color of organic compounds can often be attributed to their conjugated systems. ### Step 5: Evaluating the Statements - **Statement I:** Aniline on reaction with NaNO2 and HCl at 0°C followed by coupling with beta-naphthol gives a dark blue colored precipitate. - This statement is **incorrect** because the product is orange-red, not dark blue. - **Statement II:** The color of the compound formed in the reaction is due to extended conjugation. - This statement is **correct** as the extended conjugation in the azo compound contributes to its color. ### Conclusion Thus, the correct evaluation of the statements is: - Statement I is false. - Statement II is true. The final answer is that Statement I is incorrect while Statement II is correct. **Final Answer:** Statement I is false, Statement II is true.

To analyze the given statements, let's break down the reactions and concepts involved step by step. ### Step 1: Understanding the Reaction of Aniline with NaNO2 and HCl Aniline (C6H5NH2) reacts with sodium nitrite (NaNO2) in the presence of hydrochloric acid (HCl) at low temperatures (0°C to 5°C). This reaction leads to the formation of benzene diazonium chloride (C6H5N2Cl). **Hint:** Remember that diazonium salts are formed from primary amines in acidic conditions. ### Step 2: Formation of Benzene Diazonium Chloride ...
Promotional Banner

Topper's Solved these Questions

  • ORGANIC COMPOUNDS WITH FUNCTIONAL GROUP

    CENGAGE CHEMISTRY ENGLISH|Exercise Archives Multiple Correct|3 Videos
  • ORGANIC COMPOUNDS WITH FUNCTIONAL GROUP

    CENGAGE CHEMISTRY ENGLISH|Exercise Archives Fill In The Blanks|3 Videos
  • ORGANIC COMPOUNDS WITH FUNCTIONAL GROUP

    CENGAGE CHEMISTRY ENGLISH|Exercise Archives Single Correct|10 Videos
  • NUCLEAR CHEMISTRY

    CENGAGE CHEMISTRY ENGLISH|Exercise Archives Subjective|13 Videos
  • P-BLOCK GROUP 15 ELEMENTS - THE NITROGEN FAMILY

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises Archives (Subjective)|28 Videos

Similar Questions

Explore conceptually related problems

Aniline on treatment with nitrous acid (NaNO_2 + HCl) at 0^@C froms :

N-Methylaniline react with NaNO_2 and dilute HCl at 0-5^@ C to form.

Compound (x)(m.f=C_(7)H_(8)N) , on reaction with NaNO_(2) and conc. HCl at O^(@)C followed by beta - naphthol gives orange coloured dye. Compound (x) is :

2-4 dinitroaniline is treated with NaNO_(2) and dilute HCI at 280 K followed by reaction with anisole , forming a coloured compound . The structure of this coloured compound would be :

When aniline reacts with NaNO_2 and dil. HCl at 0^@-%^2C , the product formed is

How many toluidines on reaction with NaNO_(2)//HCl followed by H_(3)PO_(2) treatment gives Toluene.

Amongst the compounds given, the one that would form a brilliant colored dye on treatment with NaNO_2 in dil. HCl followed by addition to an alkaline solution of beta- naphthol is

Which of the following compounds reacts with NaNO_2 and HCl at 0- 4^(@)C to give alcohol/phenol?